我有这个代码我习惯将数组列表传递给另一个页面并将其显示为listview。当列表显示时,我希望能够检查一个项目并在“按钮点击”删除它,这将修改数组。
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.oppout);
final ListView lv2 = (ListView) findViewById (R.id.custom_list_view);
lv2.setClickable(true);
lv2.setAdapter(new ArrayAdapter<String>(Oppout.this,
android.R.layout.simple_list_item_checked,
Entername.playerList));
lv2.setOnItemClickListener (
new AdapterView.OnItemClickListener() {
public void onItemClick(AdapterView adapterView,
View view,int arg2, long arg3) {
int selectedPosition = adapterView.getSelectedItemPosition();
Toast.makeText(getBaseContext(), "mu"+ selectedPosition,
Toast.LENGTH_SHORT).show();
}
});
Button next = (Button) findViewById(R.id.button1);
next.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
// on click call the adapterview and delete string at selected position.
// This is my problem, am not getting how to call the adapter and deleted
// the selected item/position
int selectedPosition = adapterView.getSelectedItemPosition();
adapterView.remove(player.SelectedPosition);
Intent myIntent = new Intent (view.getContext(), Callacab.class);
startActivityForResult(myIntent, 0);
}
});
}}
答案 0 :(得分:0)
contacts.remove(索引); //你把它给你的适配器的arraylist
arrayadapter.remove(索引); //这是您将其提供给列表视图的适配器 arrayadapter.notifyDataSetChanged();
//你可以从你的arraylist或你的适配器删除然后notifyDataSetChanged();在listview中实现效果....最好从arraylist中删除它的索引将是listview项侦听器中的arg2