Question

如何在Django的Createview中声明变量，以便从模板中使用它？例如，我想在模板中使用{{place_slug}}。我从urls.py传递了这个，如下所示：

urls.py：

urlpatterns = patterns('',
    (r'^new/(?P<place_slug>[\w\-\_]+)/?$', PictureCreateView.as_view(), {}, 'upload-new'),
)

views.py：

class PictureCreateView(CreateView):
    model = Picture

    def dispatch(self, *args, **kwargs):
        self.place = get_object_or_404(Place, slug=kwargs['place_slug'])
        return super(PictureCreateView, self).dispatch(*args, **kwargs)

    def form_valid(self, form):
        more code here

Answer 1

覆盖get_context_data并设置context_data ['place_slug'] = your_slug

这样的事情：

def get_context_data(self, **kwargs):
    context = super(PictureCreateView, self).get_context_data(**kwargs)
    context['place_slug'] = self.place.slug
    return context

Django docs中的更多相关信息。

Answer 2

在模板中你可以使用 {{ title }}

class Something(generic.ListView):
        template_name = 'app/example.html'
        model = models.SomeModel
    
        def get_context_data(self, **kwargs):
            context = super(Something, self).get_context_data(**kwargs)
            context["title"] = "Some title"
            return context

Django - CreateView - 如何声明变量并在模板中使用它

2 个答案: