如何在父RECT中有效执行图像裁剪?

时间:2012-03-04 03:14:05

标签: c++ visual-c++ directx clipping rect

所以,
我正在使用C ++中的DIRECTX API,设计一个在父RECT内进行剪裁的精灵界面,比如UI窗口或其他精灵,或者你有什么。

这是因为,稍后,我将为UI窗口制作滚动功能。

我认为一张图片适合展示我想要达到的目标 Clipping

为了进行剪辑计算,至少需要四个变量/结构(从我能辨别的内容):

  • RECT:“剪裁”界限
  • D3DXIMAGE_INFO:包含图片信息,例如宽度和高度
  • 精灵位置
  • RECT函数绘制LPD3DXSPRITE->Draw():基本上,应该绘制图像的哪个部分。这就是“剪辑”的地方。

现在,如果我向您展示我的整个界面及其内部工作原理以及它如何处理变量,我认为这会令人困惑。

所以,相反,
这段代码演示了我目前是如何计算裁剪的。

void ClippingCalculation(){
    RECT parent_bounds, draw_rect;
    D3DXVECTOR2 sprite_position; //Relative to parent rect
    D3DXIMAGE_INFO img_info;

    //Fill image info
    D3DXGetImageInfoFromFile("image.png", &img_info); //Image is 100x100px

    //Define the rects
    SetRect(&parent_bounds, 0, 0, 200, 200);
    SetRect(&draw_rect, 0, 0, img_info.Width, img_info.Height); //Draw the entire image by default

    //Give it a position that makes a portion go out of parent bounds
    sprite_position = D3DXVECTOR2(150, 150); // 3/4 of the entire image is out of bounds

    //Check if completely within bounds
    bool min_x = (sprite_position.x > parent_bounds.left),
         min_y = (sprite_position.y > parent_bounds.top),
         max_x = (sprite_position.x+img_info.Width < parent_bounds.right),
         max_y = (sprite_position.y+img_info.Height < parent_bounds.bottom);

    if(min_x && min_y && max_x && max_y) 
         return; //No clipping needs to be done

    float delta_top = parent_bounds.top - sprite_position.y,
          delta_left = parent_bounds.left - sprite_position.x,    
          delta_bottom = parent_bounds.bottom - sprite_position.y,
          delta_right = parent_bounds.right - sprite_position.x;

    //Check if completely outside bounds
    bool out_left = (delta_left >= img_info.Width),
         out_top = (delta_top >= img_info.Height),
         out_bottom = (delta_bottom >= img_info.Height),
         out_right = (delta_right >= img_info.Width);

    if(out_left || out_top || out_bottom || out_right){ 
         //No drawing needs to be done, it's not even visible
         return; //No clipping
    }

    if(!min_x) draw_rect.left = delta_left;

    if(!min_x) draw_rect.top = delta_top;

    if(!max_x) draw_rect.right = delta_right;

    if(!max_y) draw_rect.bottom = delta_bottom;

    return;
}

我的问题是:

  1. 你看到代码有什么问题吗?
  2. 效率还是低效? 每次重新定位精灵,加载精灵或添加父精灵时都会完成剪辑。
  3. 数学是否稳固?我应该采用不同的方法吗?
  4. 能否以更好的方式完成,你能举例吗?

1 个答案:

答案 0 :(得分:2)

剪切RECT要比这容易得多:

clipped_rect.left= MAX(rect_a.left, rect_b.left);
clipped_rect.right= MIN(rect_a.right, rect_b.right);
clipped_rect.top= MIN(rect_a.top, rect_b.top);
clipped_rect.bottom= MAX(rect_a.bottom, rect_b.bottom);

bool completely_clipped= 
    clipped_rect.left>=clipped_rect.right || 
    clipped_rect.bottom>=clipped_rect.top

这假设Y随着你的上升而增加。找到性能最高的MINMAX平台应该非常容易。