我知道这可能听起来很愚蠢,但我是汇编语言的新手,所以请耐心等待我!
我有以下汇编代码,这是我试图做的简化版本。
1 # print.s
2 # C callable: char* print()
3
4 .data
5 output:
6 .asciz "abcd"
7
8 .text
9 .globl _printbin
10
11 _printbin:
12 pushl %ebp # set up stack frame
13 movl %esp, %ebp # save esp in ebp
14
15 movl $output, %eax # put the address of "abcd" in eax
16
17 xor %ebx, %ebx # clear ebx
18 movl $5, %ebx # put 5 in ebx (input for func)
19 movl $0, %edx # put 1 in edx (index)
20 jmp _func # call func
21
22 back1:
23 xor %ebx, %ebx # clear ebx
24 movl $7, %ebx # put 7 in ebx (input for func)
25 movl $2, %edx # put 2 in edx (index)
26 jmp _func # call func
27
28 end:
29 movl %ebp, %esp # restore esp
30 popl %ebp # restore ebp
31 ret
32
33 # take the input, add 1 to it,
34 # then print it to eax at the specified index
35 _func: # num input in %ebx, index is in %edx , print to: %eax
36 addb $0x1, %ebx # print the result to eax
37 movb %ebx, (%eax, %edx)
38 jmp back1 # how to decide wether to jump to back1 or to end?
39
40 .end
41
问题是,我如何跳转到某种“变量”标签。 (所以有时候我想跳到这个标签,但有时候又是另一个标签......那种想法。)
答案 0 :(得分:3)
如果要跳转到的地址在寄存器中,则可以进行绝对间接跳转:
jmp *%eax
查看代码后,看起来好像要执行条件跳转。
cmpl %eax, %ebx
je label1
; this is executed if %eax != %ebx
jmp end
label1:
; this is executed if %eax == %ebx
end: