Question

如果我有这样的表和数据：

ID |  Name  |  Group   

1    Apple     A    

2    Boy       A

3    Cat       B

4    Dog       C

5    Elep      C

6    Fish      C

我希望根据Group的总数从最小值到最大值进行排序，例如： A - 2条记录，B - 1条记录，C - 3条记录，因此它将成为：

3    Cat       B

1    Apple     A    

2    Boy       A

4    Dog       C

5    Elep      C

6    Fish      C

我试过

    $sql = "SELECT ID,Name FROM table ORDER BY COUNT(Group)";

但它只会为我返回一个结果。

有任何提示吗？谢谢。

Answer 1

您需要首先聚合数据，这可以使用GROUP BY子句完成：

SELECT Group, COUNT(*)
FROM table
GROUP BY Group
ORDER BY COUNT(*) DESC

DESC关键字允许您首先显示最高计数，按默认顺序显示ORDER BY按升序显示最低计数。

Answer 2

尝试：

SELECT count(*),group FROM table GROUP BY group ORDER BY group

按计数降序排序

SELECT count(*),group FROM table GROUP BY group ORDER BY count(*) DESC

这会根据group列对结果进行分组，并返回group和count，并以group顺序返回订单

Answer 3

SELECT * FROM table 
group by `Group`
ORDER BY COUNT(Group)

Answer 4

SELECT Group, COUNT(*) FROM table GROUP BY Group ORDER BY Group

或按计数排序

SELECT Group, COUNT(*) AS count FROM table GROUP BY Group ORDER BY count DESC

Answer 5

下面给出了我对你所拥有的内容。（通知组列）

SELECT
    *
FROM
    myTable
GROUP BY
    Group_value,
    ID
ORDER BY
    count(Group_value)

请告诉我这件事是否合适......

我想要得到你想要的东西......

Answer 6

尝试使用以下查询：

SELECT
    GROUP,
    COUNT(*) AS Total_Count
FROM
    TABLE
GROUP BY
    GROUP
ORDER BY
    Total_Count DESC

Answer 7

Q值。列出每个节目的名称，以及它所持有的不同次数。列出最常见的节目。

event_id show_id event_name judge_id
0101    01  Dressage        01
0102    01  Jumping         02
0103    01  Led in          01
0201    02  Led in          02
0301    03  Led in          01
0401    04  Dressage        04
0501    05  Dressage        01
0502    05  Flag and Pole   02

答：

select event_name, count(show_id) as held_times from event 
group by event_name 
order by count(show_id) desc

Answer 8

...其他答案似乎都没有问问者的要求。

对于列为“组”的名为“事物”的表：

SELECT
  things.*, counter.count
FROM
  things
LEFT JOIN (
  SELECT
    things.group, count(things.group) as count
  FROM
    things
  GROUP BY
    things.group
) counter ON counter.group = things.group
ORDER BY
  counter.count ASC;

给出：

id | name  | group | count 
---------------------------
3  | Cat   | B     | 1
1  | Apple | A     | 2
2  | Boy   | A     | 2
4  | Dog   | C     | 3
5  | Elep  | C     | 3
6  | Fish  | C     | 3

SQL按顺序排序

8 个答案: