Question

        [XmlIgnore()]
        public List<MyObject> ListMyObjects = new List<MyObject>();
        public List<string> MyProperty
        {
            get
            {
                List<string> list = new List<string>();
                foreach (MyObject obj in ListMyObjects)
                    list.Add(obj.Name);
                return list;
            }
            set
            {
                foreach (string name in value)
                    ListMyObjects.Add(new MyObject(name));
            }
        }

为什么MyPropery没有序列化？我正在使用Xml Serializer。

Answer 1

有人请格式化我的代码，它不是在iPad上格式化。

请试试这个，

public string[] MyProperty
        {
            get
            {
                List<string> list = new List<string>();
                foreach (MyObject obj in ListMyObjects)
                    list.Add(obj.Name);
                return list.ToArray();
            }
            set
            {
                foreach (string name in value)
                    ListMyObjects.Add(new MyObject(name));
            }
        }

Answer 2

对我来说工作正常..检查一下..

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Serialization;
using System.IO;

namespace Serialization_Xml
{
    class Program
    {
        static void Main(string[] args)
        {
            Data data = new Data();
            List<string> mylist = new List<string>();
            mylist.Add("A");
            mylist.Add("B");
            data.MyProperty = mylist;
            FileStream fs = new FileStream("Data.xml", FileMode.Create);
            XmlSerializer serializer= new XmlSerializer(typeof(Data));
            serializer.Serialize(fs, data);
        }
    }

   public class Data
    {
        [XmlIgnore()]
        public List<MyObject> ListMyObjects = new List<MyObject>();
        public List<string> MyProperty
        {
            get
            {
                List<string> list = new List<string>();
                foreach (MyObject obj in ListMyObjects)
                    list.Add(obj.Name);
                return list;
            }
            set
            {
                foreach (string name in value)
                    ListMyObjects.Add(new MyObject(name));
            }
        }

    }

    public class MyObject
    {
        public string Name;
        public MyObject(string name)
        {
            Name = name;
        }
    }
}

输出：

<?xml version="1.0"?>
<Data xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <MyProperty>
    <string>A</string>
    <string>B</string>
  </MyProperty>
</Data>

属性未序列化

2 个答案: