我有一个多维数组,如下所示:
Array
(
[0] => Array
(
[0] => Array
(
[description] => UPS Ground
[delivery-time] => 1-5 business days
[shipping-amount] => 1299
)
[1] => Array
(
[description] => UPS 3 Day Select
[delivery-time] => 3 business days
[shipping-amount] => 2459
)
[2] => Array
(
[description] => UPS 2nd Day Air
[delivery-time] => 2 business days
[shipping-amount] => 3239
)
)
[1] => Array
(
[0] => Array
(
[description] => UPS Ground
[delivery-time] => 1-5 business days
[shipping-amount] => 864
)
[1] => Array
(
[description] => UPS 3 Day Select
[delivery-time] => 3 business days
[shipping-amount] => 1109
)
[2] => Array
(
[description] => UPS 2nd Day Air
[delivery-time] => 2 business days
[shipping-amount] => 1633
)
[3] => Array
(
[description] => UPS Overnight
[delivery-time] => 1 business day
[shipping-amount] => 3528
)
)
)
我正在努力实现三件事:
shipping-amount
的值description
跨维度array
包含其他维度不存在的description
,则将其删除可能有几个第一级数组(不仅仅是这里显示的2个),但这和维度一样深。我正在寻找以下结果:
Array
(
[0] => Array
(
[description] => UPS Ground
[delivery-time] => 1-5 business days
[shipping-amount] => 2163
)
[1] => Array
(
[description] => UPS 3 Day Select
[delivery-time] => 3 business days
[shipping-amount] => 3568
)
[2] => Array
(
[description] => UPS 2nd Day Air
[delivery-time] => 2 business days
[shipping-amount] => 4872
)
)
提前致谢!
答案 0 :(得分:2)
我认为这样可行:
$final=array(); // the final array
$count=array(); // keeps track of instances of each description
$loops=count($array);
for($a=0;$a<$loops;$a++){
foreach($array[$a] as $s){ //loop through child arrays
if($count[$s['description']]>0){ //check if description exists in $count
foreach($final as $k=>$v){ //add sums to the final if it does exist
if($final[$k]['description']==$s['description']){$final[$k]['shipping-amount']+=$s['shipping-amount'];}
}
}else{ //if it doesn't exist in the count array, add it to the final array
$final[]=$s;
}
$count[$s['description']]++;//update the count array
}
}
//Unset singletons, using the count array
foreach($count as $k=>$v){
if($v==1){
foreach($final as $key=>$val){
if($final[$key]['description']==$k){unset($final[$key]);}
}
}
}
print_r($final);
过去两天我一直困扰着一个问题并感受到你,所以我希望这会有所帮助。
答案 1 :(得分:0)
我不打算编写代码,因为我同意 deceze 。
尽管如此,我的推荐是一个自定义功能:
鉴于您的具体要求不是一个神奇的PHP函数,它可以做到这一点。然而,您可以在自定义函数中使用数十个PHP array functions。
如果您需要有关某件作品的帮助,请更新您的帖子或提出新问题。
答案 2 :(得分:0)
我建议使用array_walk函数和回调来处理您对添加和唯一性的特定要求。