Question

好吧，如果觉得这应该非常简单并且通过像array_merge()或array_merge_recursive这样的函数来完成，但我无法弄明白。我有两个简单的数组，如下面的（简化）示例。我只想根据它们的索引将它们合并到一个数组中。

$ array 1：

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
  )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
  )
)

等等......

$ array2：

Array ( 
  [0] => Array ( 
        [distance] => 1000 
        [time] => 10 
  )  
  [1] => Array ( 
        [distance] => 1500 
        [time] => 15 
  )
)

$ desiredResult：

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
        [distance] => 1000 
        [time] => 10 
 )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
        [distance] => 1500 
        [time] => 15 
 )
)

当我尝试使用合并函数合并它们时，我只能得到这个：

$ unDesiredResult：

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
  )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
  )
  [2] => Array ( 
        [distance] => 1000 
        [time] => 10 
  )  
  [3] => Array ( 
        [distance] => 1500 
        [time] => 15 
  )
)

我是否需要循环将第二组推入第一组，或者可以使用现有功能完成？

Answer 1

我认为没有为你做这个功能，你必须循环。

$result = array();
foreach($array1 as $key=>$val){ // Loop though one array
    $val2 = $array2[$key]; // Get the values from the other array
    $result[$key] = $val + $val2; // combine 'em
}

或者您可以将数据推送到$ array1，因此您需要创建第3个数组：

foreach($array1 as $key=>&$val){ // Loop though one array
    $val2 = $array2[$key]; // Get the values from the other array
    $val += $val2; // combine 'em
}

Answer 2

您需要使用循环。尝试创建一个函数：

function addArray( array &$output, array $input ) {
    foreach( $input as $key => $value ) {
        if( is_array( $value ) ) {
            if( !isset( $output[$key] ) )
                $output[$key] = array( );
            addArray( $output[$key], $value );
        } else {
            $output[$key] = $value;
        }
    }
}

然后：

$combinedArray = array( );
addArray( $combinedArray, $array1 );
addArray( $combinedArray, $array2 );

Answer 3

示例必须合并数组：

 [location_coordinates] => Array
                                (
                                    [0] => 36.037939100000,-78.905221600000
                                    [1] => 36.004398400000,-78.936084600000
                                )

                            [tm_field_reference_locations$field_location_address$city] => Array
                                (
                                    [0] => Durham
                                    [1] => Durham
                                )

                            [doctor_city] => Array
                                (
                                    [0] => Durham
                                    [1] => Durham
                                )

                            [tm_field_reference_locations$field_location_address$street] => Array
                                (
                                    [0] => 407 Crutchfield Street
                                    [1] => 40 Duke Medicine Circle
                                )

                            [tm_field_reference_locations$field_office_phone] => Array
                                (
                                    [0] => 919-479-4120
                                    [1] => 919-613-0444
                                )

                            [sm_field_reference_locations$title] => Array
                                (
                                    [0] => Duke Regional Hospital Spine and Neurosciences
                                    [1] => Duke Spine Center
                                )

如下所示循环：

        $address= array();
for($n=0; $n<sizeof($kolDetails['location_coordinates']); $n++){
    $address[$n]['org_institution_id']=$kolDetails['sm_field_reference_locations$title'][$n];
    $address[$n]['longitude']=$kolDetails['location_coordinates'][$n];
    $address[$n]['City']=$kolDetails['doctor_city'][$n];
    $address[$n]['address1']=$kolDetails['tm_field_reference_locations$field_location_address$street'][$n];                 
    $address[$n]['phone_number']=$kolDetails['tm_field_reference_locations$field_office_phone'][$n];        
     }
     $kolextra['adress']=$address;
     pr($kolextra['adress']);
     $address = array();

Answer 4

我会以一个间隔稍微改变一下。这假设您的值始终被锁定，并且array1的第一条记录始终与array2的第一条记录对应：

$i = 0; // sets counter
$end = count($array1); // finds record number
while($i <= $end){ //for each record in the array
    $array1[$i]['distance'] = $array2[$i]['distance'];  //match up array values
    $array1[$i]['time'] = $array2[$i]['time'];  //match up array values
    $i++; //iterate
}

祝你好运！

按索引合并两个数组

4 个答案: