Question

我有以下查询，我正在尝试生成四列，买方，来源，潜在客户总数和退回的潜在客户。

问题在于包含一个包含总线数的列。返回是我的数据库中的一个列，其中值为0或1.所以返回的是1的所有内容，但对于已购买的潜在客户，我需要的所有内容为0.当我运行以下查询时，所有购买的潜在客户最终都是0.如何修复子查询以获得所需的结果。

SELECT 
    ba.buyer, 
    l.source,
    (SELECT COUNT(*) FROM lead_status WHERE lead_id = l.id AND returned != 1) AS 'Bought Leads',
    SUM(l.returned) AS 'Returned_Leads' 
FROM lead_status AS ls 
    LEFT JOIN leads AS l ON ls.lead_id = l.id
    LEFT JOIN buyer_account AS ba ON ba.lead_buyer_id = ls.lead_buyer_id
WHERE l.origin = 'PING_POST' 
    AND ls.discriminator IN('AUTO_POST','HOME_POST','HEALTH_POST','LIFE_POST')
    AND DATE(ls.create_date) BETWEEN '2012-02-01' AND '2012-02-31'
    AND l.sold = 1 AND ls.winner = 1 AND l.test = 0 AND l.returned = 1
GROUP BY ls.buyer, l.source;

Answer 1

只需将子查询替换为：

SUM(1-l.returned)

只要它是一个位字段，否则你应该使两个和操作CASE语句，即sum（在0时返回的情况，然后在0结束时返回）。

Answer 2

尝试

SUM( abs(l.returned-1) )

如果返回0，则返回-1
如果返回为1，则返回0

取abs（）值会得到+1，所以你的SUM（）应该可以工作

Answer 3

我认为你可以做一个替代方案，如果它是二进制1或0：

SELECT 
    ba.buyer, 
    l.source,
    COUNT(l.returned) - SUM(l.returned) AS 'Bought Leads',
    SUM(l.returned) AS 'Returned_Leads' 
FROM lead_status AS ls 
    LEFT JOIN leads AS l ON ls.lead_id = l.id
    LEFT JOIN buyer_account AS ba ON ba.lead_buyer_id = ls.lead_buyer_id
WHERE l.origin = 'PING_POST' 
    AND ls.discriminator IN('AUTO_POST','HOME_POST','HEALTH_POST','LIFE_POST')
    AND DATE(ls.create_date) BETWEEN '2012-02-01' AND '2012-02-31'
    AND l.sold = 1 AND ls.winner = 1 AND l.test = 0 AND l.returned = 1
GROUP BY ls.buyer, l.source;

添加子查询

3 个答案: