Question

我正在为我的工作构建一个数据库，但我无法弄清楚如何构建此查询。

与我的问题相关的表是：

工作

Surgical_Planning - 作为外键的工作，存在一些工作，不存在其他工作

Medical_Model - 具有外键作业，与作业1对1的关系

这是一个有效的查询，我没有任何有关手术计划的信息

    SELECT
    job,
    physician_idphysician as Physician,
    patient_idpatient as Patient,
    status,
    DATE_FORMAT(scan_date, '%M %e, %Y, %l:%i%p') as Scan_Date,
    DATE_FORMAT(timestamp, '%M %e, %Y, %l:%i%p') as Recieved,
    DATE_FORMAT(date_required, '%M %e, %Y, %l:%i%p') as Date_Required
    FROM
    job, patient_has_physician as phys, Scan, Medical_Model as med
    WHERE
    Scan.job_job = job AND phys.job_job = job
    AND med.job_job = job AND job.type =  'medical

我想我想要做一个左连接，以便按顺序显示每个作业，上面的查询中包含所有信息，但是当有一个作业的Surgical_Planning时，我希望有一个列为那也是。这是我的尝试不起作用

    SELECT
    job,
    physician_idphysician as Physician,
    patient_idpatient as Patient,
    status,
    DATE_FORMAT(scan_date, '%M %e, %Y, %l:%i%p') as Scan_Date,
    DATE_FORMAT(timestamp, '%M %e, %Y, %l:%i%p') as Recieved,
    DATE_FORMAT(date_required, '%M %e, %Y, %l:%i%p') as Date_Required
    FROM
    job, patient_has_physician as phys, Scan, Medical_Model as med

    LEFT JOIN Surgical_Planning ON job.job = Surgical_Planning.job_job
    AND Scan.job_job = job AND phys.job_job = job
    AND med.job_job = job AND job.type = 'medical'

我可以按照我想要的方式运行这个基本的左连接，但是如果我想添加更多像上面这样的列，它就不起作用。

    SELECT job, planning_id
    FROM job
    LEFT JOIN Surgical_Planning ON job = Surgical_Planning.job_job

是否也可以使用子查询？我可以找出这些更基本的查询，但真的遇到了这些更复杂的连接和子查询问题。任何建议表示赞赏。

编辑---作业表架构

- 表mmrl。job

DROP TABLE IF EXISTS mmrl。job;

CREATE TABLE IF NOT NOT EXISTS mmrl。job（

job INT（11）NOT NULL AUTO_INCREMENT，

type VARCHAR（45）NULL，

status VARCHAR（45）NULL DEFAULT NULL，

timestamp TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP on UPDATE CURRENT_TIMESTAMP，

PRIMARY KEY（job））

ENGINE = InnoDB

DEFAULT CHARACTER SET = latin1;

Answer 1

变化

LEFT JOIN Surgical_Planning ON job.job = Surgical_Planning.job_job
AND Scan.job_job = job AND phys.job_job = job
AND med.job_job = job AND job.type = 'medical'

到

LEFT JOIN Surgical_Planning ON job.job = Surgical_Planning.job_job
WHERE Scan.job_job = job AND phys.job_job = job
AND med.job_job = job AND job.type = 'medical'

编辑：

左连接针对实际LEFT JOIN语法左侧的表。将作业移至列表的末尾，然后重试。

FROM patient_has_physician as phys, Scan, Medical_Model as med, job

mysql左连接多列

1 个答案: