Question

现在我需要下载zip文件并将其解压缩到Android中的固定SD卡文件中。我已经可以下载文件了，但我无法解压缩zip文件。我发现的问题是zipinputstream为空。下面的代码在java编程中都成功了，我不明白为什么这段代码不能在android中运行。

public void getZipFiles(String filename, String destinationname){
        try{
            Log.i("filename",filename);
            Log.i("destinationname",destinationname);
            File d = new File(destinationname);

            if(!d.isDirectory()){
                d.mkdir();
            }


            byte[] buf = new byte[1024];
            ZipInputStream zipinputstream = null;
            zipinputstream = new ZipInputStream(
                new FileInputStream(new File(filename)));
            ZipEntry zipentry;

            Log.i("read", ""+zipinputstream.read());
            zipentry = zipinputstream.getNextEntry();

            while (zipentry != null){ 
                //for each entry to be extracted
                String entryName = zipentry.getName();
                System.out.println("entryname "+entryName);
                int n;
                FileOutputStream fileoutputstream;

                fileoutputstream = new FileOutputStream(destinationname+entryName);             

                while ((n = zipinputstream.read(buf, 0, 1024)) > -1)
                    fileoutputstream.write(buf, 0, n);

                fileoutputstream.close(); 
                zipinputstream.closeEntry();
                zipentry = zipinputstream.getNextEntry();

            }//while

            zipinputstream.close();

        }catch (IOException e){

            e.printStackTrace();
            System.out.println("!"+e.toString());
            Log.e("err", e.toString());
        }
    }

这是我的php下载文件代码

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<body>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<?php
if($_GET['f']!=null){
    $file=$_GET['f'];//file name
    $url="http://58.176.4.199/"; //path
/*  $num=date("Ymds");  
    $num =1;*/
    header("Content-type:application");
    header("Content-Disposition: attachment; filename=".$file); 
    //readfile($url.str_replace("@","",$file)); 
    readfile($file);
    exit(0);
}else{
    echo "No file....";
}
?>

</body>
</html>

android unzip文件，没有提取文件

0 个答案: