Question

我这里有Linq-to-SQL代码，它在各自的表中将数据提交到数据库中， PatientInformation和ResponsibleParty：

public void addPatientInformation() { 
   using(DbClassesDataContext myDb = new DbClassesDataContext(dbPath)){
      PatientInfo patientInfo = new PatientInfo();

      patientInfo.Phy_ID = physcianID;
      patientInfo.Pat_First_Name = txtFirstName.Text;
      patientInfo.Pat_Middle_Name = txtMiddleName.Text;
      patientInfo.Pat_Last_Name = txtLastName.Text;
      patientInfo.Pat_Gender = cmbGender.Text;
      patientInfo.Pat_Marital_Status = cmbMaritalStatus.Text;
      patientInfo.Pat_Date_Of_Birth = dtpDOB.Value;
      patientInfo.Pat_Home_Add = txtHomeAdd.Text;
      patientInfo.Pat_Home_Num = txtPhone.Text;
      patientInfo.Pat_Work_Add = txtWorkAdd.Text;
      patientInfo.Pat_Work_Num = txtWorkPhone.Text;
      patientInfo.Pat_Prim_Physician = txtPrimPhysician.Text;
      patientInfo.Pat_Ref_Physician = txtRefePhysician.Text;

      myDb.PatientInfos.InsertOnSubmit(patientInfo);
      myDb.SubmitChanges();
   }
}

public void addResponsiblePartyInformation() { 
   using(DbClassesDataContext myDb = new DbClassesDataContext(dbPath)){
      ResponsibleParty responsibleParty = new ResponsibleParty();

      responsibleParty.Res_First_Name = txtResFirstName.Text;
      responsibleParty.Res_Middle_Init = txtResMiddleName.Text;
      responsibleParty.Res_Last_Name = txtResLName.Text;
      responsibleParty.Res_Gender = cmbResGender.Text;
      responsibleParty.Res_Marital_Status = cmbResMaritalStatus.Text;
      responsibleParty.Res_Date_Of_Birth = dtpResDOB.Value;
      responsibleParty.Res_Home_Add = txtResHomeAdd.Text;
      responsibleParty.Res_Home_Num = txtResPhone.Text;
      responsibleParty.Res_Work_Add = txtResWorkAdd.Text;
      responsibleParty.Res_Work_Num = txtResWorkPhone.Text;

      myDb.ResponsibleParties.InsertOnSubmit(responsibleParty);
      myDb.SubmitChanges();
   }

一个名为

的方法

public void submitInformationToDatabase() {
            addPatientInformation();
            addResponsiblePartyInformation();
            MessageBox.Show("Patient Demographics Has Been added.");
        }

有没有办法可以立刻提交？

Answer 1

两个选项：

传入数据上下文，不要每次都调用SubmitChanges()（也许可以选择）
使用交易

对于第二种情况，可以使用TransactionScope来执行此操作，而无需更改这两种方法：

using(var tran = new TransactionScope()) {
    method1(...);
    method2(...);
    tran.Complete();
}

或使用其他方法（添加可选参数后）：

using(var ctx = new SomeDataContext(...)) {
    method1(ctx, ..., submitChanges: false);
    method2(ctx, ..., submitChanges: false);
    ctx.SubmitChanges();
}

Answer 2

如果您可以将代码重构为类似下面示例的内容，则两个记录都将插入到同一submit中。

using(DbClassesDataContext myDb = new DbClassesDataContext(dbPath)){

      myDb.PatientInfos.InsertOnSubmit(patientInfo);
      myDb.ResponsibleParties.InsertOnSubmit(responsibleParty);
      myDb.SubmitChanges();
}

Answer 3

使用两种方法将连接作为参数传递，并使用System.Transaction：

public void submitInformationToDatabase() {
         using (System.Transactions.TransactionScope tr = new System.Transactions.TransactionScope())
           {
            System.Data.SqlClient.SqlConnection con = new System.Data.SqlClient.SqlConnection(dbPath);
            con.Open();
            addPatientInformation(con);
            addResponsiblePartyInformation(con);
            tr.Complete();
           }
            MessageBox.Show("Patient Demographics Has Been added.");
        }

使用Linq-to-SQL同时将数据插入到不同的表中

3 个答案: