Question

我有以下html，它显示3个文本框和一个添加按钮：

<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title></title>
</head>
<body>
    <form id="form1" runat="server">
    <div id="container">
    <div id="line-item">
    <asp:TextBox ID="txtLineNumber" runat="server"></asp:TextBox>
    <asp:TextBox ID="txtQty" runat="server"></asp:TextBox>
    <asp:TextBox ID="txtItemCode" runat="server"></asp:TextBox>
    <asp:ImageButton ID="imgBtnAddNewLineItem" ImageUrl="~/images/add_button.jpg" 
    runat="server" />
   </div>
   </div>
   </form>

   <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2
   /jquery.min.js">
   </script>
   <script src="js/invoice.js" type="text/javascript"></script>
</body>
</html>

当用户点击添加按钮时，我想创建另一个带有项目ID的div并将其放在下一行。我创建了一个js文件，但我不知道该怎么做？

这是我到目前为止所做的：

var itemCount = 0;

function getLineItem(number) {
    var div = document.createElement('div');

   $(div).attr("id", "lineitem" + number);
   var t1 = getTextbox("txt" + number.toString() + "1");
   var t2 = getTextbox("txt" + number.toString() + "2");
   var t3 = getTextbox("txt" + number.toString() + "3");

   $(div).append(t1);
   $(div).append(t2);
   $(div).append(t3);

   return $(div);
}

function getTextbox(id) {
    var textbox = document.createElement('input');
    $(textbox).attr("id", id);
    return $(textbox);
}


var lineItemCount = 0;

   $('#imgBtnAddNewLineItem').click(function() {

    lineItemCount++;

   $('#line-item').clone().attr('id',getLineItem(lineItemCount)).appendTo('#container');
    });
});

Answer 1

$(document).ready(function() {
    $('#imgBtnAddNewLineItem').click(function() {
        $('#container').append('<div></div>');
    });
});

更新2

像这样创建一个普通按钮：

<input type="button" id="imgBtnAddNewLineItem" value="Add lineitem" />

更新 **这也会通过评论等进行更新。**

//Count the lineItems to make sure they are unique
var lineItemCount = 0;

//On document ready 
$(document).ready(function() {
    //On button click
    $('#imgBtnAddNewLineItem').click(function(e) {
        /*
           ADD THE FOLLOWING LINE TO PREVENT THE POSTBACK
           P.S. - Make sure you pass -e- to this function... 

         */
         e.preventDefault();



         //Increase the lineitemcount
         lineItemCount++;
         //Add a new lineitem to the container, pass the lineItemCount to make sure getLineItem() can generate a unique lineItem with unique Textbox ids
         $(container).append(getLineItem(lineItemCount));
    });
});

//Create a new DIV with Textboxes
function getLineItem(number) {
    var div = document.createElement('div');
    //Give the div a unique id

    div.setAttribute('id','lineitem_' + number);

    //pass unique values to the getTextbox() function
    var t1 = getTextbox('txt_' + number + '_1');
    var t2 = getTextbox('txt_' + number + '_2');
    var t3 = getTextbox('txt_' + number + '_3');

    div.appendChild(t1);
    div.appendChild(t2);
    div.appendChild(t3);

    return div;
}

//Create a textbox, make sure the id passed to this function is unique...
function getTextbox(id) {
    var textbox = document.createElement('input');
    textbox.setAttribute('id',id);
    textbox.setAttribute('name',id);
    return textbox;
}

Answer 2

尝试这样的事情：

$(document).ready(function() {
  $('#imgBtnAddNewLineItem').click(function() {
    var container = $("#container");
    var line = $('#line-item').clone().attr("id", "line-item-2")
    var lineCount = container.children().length + 1;
    line.attr("id", line.attr("id") + "-" + lineCount);
    line.find(":text").each(function() {
      // IDs need to be unique
      $(this).attr("id", $(this).attr("id") + "-" + lineCount);
      $(this).attr("name", $(this).attr("name") + "-" + lineCount);
      // clear the value since we're cloning a line that may have values in it
      $(this).val("");
    });
    container.append(line);
  });
});

注意：您需要更改ID。

Answer 3

您可以使用.append()方法或.html()

如何使用JQuery动态添加div？

3 个答案: