无法使用删除功能从SD卡中删除文件

时间:2012-03-02 11:27:58

标签: android file-io sd-card

在我的应用程序中,我将表格保存为图像。用户可以在打开后删除文件(图像)。当用户点击“打开”时,我使用以下代码打开图像:

File directory=new  File(extStorageDirectory,File.separator+"myDirectory"+File.separator);
File fileInDirectory=new File(directory, fileName); 

//I save the opened file's path n "filePath"
filePath=fileInDirectory.getAbsolutePath();
Bitmap bitmap = BitmapFactory.decodeFile(fileInDirectory.getAbsolutePath());  
ImageView ivv=(ImageView) findViewById(R.id.imageView);
ivv.setImageBitmap(bitmap);

//I enable the delete button
deleteFile.setEnabled(true);

文件打开没有任何问题。当用户点击“删除”时,我会执行以下操作:

  //I create a file using the filePath I saved earlier
  File file=new File(filePath);
  file.delete();                      

但它不会从SD卡中删除该文件。我已经验证并且filePath是正确的。我也尝试过deleteFile(String)函数:

 deleteFile(fileNeme);
 //fileName is the name of my file that I save earlier and I've verified it by printing it and there is no problem. 

我已经把

    <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

在我的清单文件中。所以我不认为这是权利问题,因为我能够从SD卡上写和读。

有办法做到这一点吗?

编辑: 这是我保存文件的代码。

this.save.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
AlertDialog.Builder alert=new AlertDialog.Builder(LensCalculator.this);
alert.setTitle("Save");
alert.setMessage("Enter file name");

final EditText input=new EditText(MyActivity.this);
alert.setView(input);

alert.setPositiveButton("OK", new DialogInterface.OnClickListener(){
    @Override
    public void onClick(DialogInterface dialog, int which) {
                    // TODO Auto-generated method stub
    TableView table=(TableView) findViewById(R.id.tableId);
    table.setDrawingCacheEnabled(true);
    Bitmap b=table.getDrawingCache();
    Canvas canvas=new Canvas(b);
    canvas.drawBitmap(b, 0f, 175f, null);
    OutputStream outStream = null;
    String fileName=input.getText().toString();
    File directory =new File(extStorageDirectory+File.separator+"myDirectory"+File.separator);
    if(!directory.mkdir())
           directory.mkdir();
    File file = new File(directory, fileName);
    try {
        outStream = new FileOutputStream(file);
        b.compress(Bitmap.CompressFormat.PNG, 100, outStream);
        FileOutputStream fOut=openFileOutput("public.dat", Context.MODE_PRIVATE|Context.MODE_APPEND);
        OutputStreamWriter osw=new OutputStreamWriter(fOut);
        osw.write(fileName+"\n");

        osw.close();
        fOut.close();
        outStream.close();
        table.destroyDrawingCache();
    } catch (FileNotFoundException e) {
        // TODO Auto-generated catch block
            e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
            e.printStackTrace();
    }
}
});

2 个答案:

答案 0 :(得分:0)

试试:yourFile.delete();

答案 1 :(得分:0)

如果路径正确&amp;你有权限&amp;文件未打开然后它应该工作。这是一个神秘的情况。你有任何例外吗?确保你没有这样的东西:

catch(Exception e) { 
 // Do nothing
}

这一个是遥远的可能性,但无论如何。你如何检查文件被删除?请记住,当您将手机连接到计算机并且安装了SD卡时,您的应用程序将无法访问它(因此无法删除该文件)。

另一种远程可能性......尝试添加:

/*...*/
ivv.setImageBitmap(bitmap);
bitmap.recycle();
bitmap = null;

修改

我不明白为什么你需要这么复杂的代码,这可能会简单得多:

File file = new File(directory, fileName);
try {
    outStream = new FileOutputStream(file);
    b.compress(Bitmap.CompressFormat.PNG, 100, outStream);
    FileOutputStream fOut=openFileOutput(fileName, Context.MODE_PRIVATE|Context.MODE_APPEND);
    OutputStreamWriter osw=new OutputStreamWriter(fOut);
    osw.write(fileName+"\n");

    osw.close();
    fOut.close();
    outStream.close();
    table.destroyDrawingCache();
} catch (FileNotFoundException e) {
    // TODO Auto-generated catch block
        e.printStackTrace();
} catch (IOException e) {
    // TODO Auto-generated catch block
        e.printStackTrace();
}

像这样:

FileOutputStream out = null;
try {
       out = new FileOutputStream(directory + fileName);
       bmp.compress(Bitmap.CompressFormat.PNG, 100, out);
} catch (Exception e) {
       e.printStackTrace();
} finally {
       try {
           if(out != null) {
               out.close();
           }
       }
       catch (Exception e) {
           e.printStackTrace();
       }
}