Question

我需要帮助sql select from multiply tables。

表：

s_products
- id
- name
- url
- brand_id

s_products_categories
- product_id
- category_id

s_brands
- id
- name
- url

s_categories
- id
- name
- url

比较

s_products.id =  s_products_categories.product_id
s_categories.id = s_products_categories.category_id
s_products.brand_id = s_brands.id

结果需要：

1）$products['s_categories.url']['s_brands.url']['s_products.url'] = 's_products.name';

2）$brands['s_categories.url']['s_brands.url'] = 's_brands.name';

你能帮助我在一个选择（或更多）中做到吗？

Answer 1

select *yourcolumnsname*
from s_products INNER JOIN  s_products_categories
on s_products.id =  s_products_categories.product_id
INNER JOIN s_categories.id 
on s_categories.id = s_products_categories.category_id;

Answer 2

SELECT s_categories.url as url1, s_products.url as url2, s_products.name as name 
FROM s_products 
INNER JOIN s_products_categories on s_products.id   = s_products_categories.product_id 
INNER JOIN s_categories          on s_categories.id = s_products_categories.category_id

Answer 3

尝试：

select c.url  category_url,
       c.name category_name,
       b.url  brand_url,
       b.name brand_name,
       p.url  product_url,
       p.name product_name
from s_products p
join s_brands b on p.brand_id = b.id
join s_products_categories pc on p.id = pc.product_id
join s_categories c on pc.category_id = c.id

要查看特定字段的组合（例如，category_url与brand_url），请在distinct之后立即添加select，并删除不需要的字段。

在一个结果中加入更多表

3 个答案: