我正在尝试使用杂志api获取以下json内容。 json的输出是这样的。我希望下面的json转换为php数组。
{
"bpath": "http://www.sampledomain.com/",
"clist": [
{
"cid": "11",
"display_type": "grid",
"ctitle": "abc",
"acount": "71",
"alist": [
{
"aid": "6865",
"adate": "2 Hours ago",
"atitle": "test",
"adesc": "test desc",
"aimg": "",
"aurl": "?nid=6865",
"weburl": "news.php?nid=6865",
"cmtcount": "0"
},
{
"aid": "6857",
"adate": "20 Hours ago",
"atitle": "test1",
"adesc": "test desc1",
"aimg": "",
"aurl": "?nid=6857",
"weburl": "news.php?nid=6857",
"cmtcount": "0"
}
]
},
{
"cid": "1",
"display_type": "grid",
"ctitle": "test1",
"acount": "2354",
"alist": [
{
"aid": "6851",
"adate": "1 Days ago",
"atitle": "test123",
"adesc": "test123 desc",
"aimg": "",
"aurl": "?nid=6851",
"weburl": "news.php?nid=6851",
"cmtcount": "7"
},
{
"aid": "6847",
"adate": "2 Days ago",
"atitle": "test12345",
"adesc": "test12345 desc",
"aimg": "",
"aurl": "?nid=6847",
"weburl": "news.php?nid=6847",
"cmtcount": "7"
}
]
},
]
}
我的代码看起来像这样。
<?php
$json_url = "http://api.testmagazine.com/test.php?type=menu";
$json = file_get_contents($json_url);
$data = json_decode($json, TRUE);
echo "<pre>";
print_r($data);
echo "</pre>";
?>
上面的代码返回一个空数组。 :( 如何将上述JSON转换为php对象数组。 我很无奈。
由于 Haan的
答案 0 :(得分：20)
您提供的JSON示例无效。使用此JSON验证器http://jsonlint.com/在线检查。您需要删除第59行的额外逗号。
您有一个有效的json，您可以使用此代码将其转换为数组。
json_decode（$ json，true）;
Array
(
[bpath] => http://www.sampledomain.com/
[clist] => Array
(
[0] => Array
(
[cid] => 11
[display_type] => grid
[ctitle] => abc
[acount] => 71
[alist] => Array
(
[0] => Array
(
[aid] => 6865
[adate] => 2 Hours ago
[atitle] => test
[adesc] => test desc
[aimg] =>
[aurl] => ?nid=6865
[weburl] => news.php?nid=6865
[cmtcount] => 0
)
[1] => Array
(
[aid] => 6857
[adate] => 20 Hours ago
[atitle] => test1
[adesc] => test desc1
[aimg] =>
[aurl] => ?nid=6857
[weburl] => news.php?nid=6857
[cmtcount] => 0
)
)
)
[1] => Array
(
[cid] => 1
[display_type] => grid
[ctitle] => test1
[acount] => 2354
[alist] => Array
(
[0] => Array
(
[aid] => 6851
[adate] => 1 Days ago
[atitle] => test123
[adesc] => test123 desc
[aimg] =>
[aurl] => ?nid=6851
[weburl] => news.php?nid=6851
[cmtcount] => 7
)
[1] => Array
(
[aid] => 6847
[adate] => 2 Days ago
[atitle] => test12345
[adesc] => test12345 desc
[aimg] =>
[aurl] => ?nid=6847
[weburl] => news.php?nid=6847
[cmtcount] => 7
)
)
)
)
)
答案 1 :(得分：8)
你JSON不是一个有效的字符串，就像P. Galbraith上面告诉你的那样。
这是解决方案。
<?php
$json_url = "http://api.testmagazine.com/test.php?type=menu";
$json = file_get_contents($json_url);
$json=str_replace('},
]',"}
]",$json);
$data = json_decode($json);
echo "<pre>";
print_r($data);
echo "</pre>";
?>
使用此代码，它将适合您。
答案 2 :(得分：2)
检查一些拼写错误'，'
<?php
//file_get_content(url);
$jsonD = '{
"bpath":"http://www.sampledomain.com/",
"clist":[{
"cid":"11",
"display_type":"grid",
"ctitle":"abc",
"acount":"71",
"alist":[{
"aid":"6865",
"adate":"2 Hours ago",
"atitle":"test",
"adesc":"test desc",
"aimg":"",
"aurl":"?nid=6865",
"weburl":"news.php?nid=6865",
"cmtcount":"0"
},
{
"aid":"6857",
"adate":"20 Hours ago",
"atitle":"test1",
"adesc":"test desc1",
"aimg":"",
"aurl":"?nid=6857",
"weburl":"news.php?nid=6857",
"cmtcount":"0"
}
]
},
{
"cid":"1",
"display_type":"grid",
"ctitle":"test1",
"acount":"2354",
"alist":[{
"aid":"6851",
"adate":"1 Days ago",
"atitle":"test123",
"adesc":"test123 desc",
"aimg":"",
"aurl":"?nid=6851",
"weburl":"news.php?nid=6851",
"cmtcount":"7"
},
{
"aid":"6847",
"adate":"2 Days ago",
"atitle":"test12345",
"adesc":"test12345 desc",
"aimg":"",
"aurl":"?nid=6847",
"weburl":"news.php?nid=6847",
"cmtcount":"7"
}
]
}
]
}
';
$parseJ = json_decode($jsonD,true);
print_r($parseJ);
?>