Question

如何使用此代码打印此结果我不认识自己我做错了什么可以帮助我

<?php
$brush_price = 5;

echo "<table border=\"1\" align=\"center\">";
echo "<tr><th>Quantity</th>";
echo "<th>Price</th></tr>";
for ( $counter++ = 10; $counter <= 100; $counter += 10) {
    echo "<tr><td>";
    echo $counter;
    echo "</td><td>";
    echo $brush_price * $counter;
    echo "</td></tr>";
}
echo "</table>";    
?>

输出： -

Quantity Price
10        50
20        100
30        150

Answer 1

我想你想要这样的东西：

for ( $counter = 10; $counter <= 100; $counter += 10)

Answer 2

这里你去：相同的输出，用Javascript编写。把它放在你的html文件中。

var brush_price = 5;

document.write("<table border='1' align='center'>");
document.write("<tr><th>Quantity</th><th>Price</th></tr>");

for(var counter = 10; counter <= 100; counter += 10){
    document.write("<tr><td>" + counter + "</td><td>" + (counter * brush_price) + "</td></tr>");
}

document.write("</table>");

Answer 3

您的PHP代码（您输错了标签，它应该是PHP）：

for ( $counter++ = 10; $counter <= 100; $counter += 10)

似乎你打算将$ counter变量初始化为某个初始值（0，也许？） $ counter ++表示$ counter = $ counter + 1，它是一个表达式。你不能为表达式赋值，它会抛出无效的左侧赋值错误。

尝试更改以下代码...

for ( $counter = 10; $counter <= 100; $counter += 10)

Javascript等效：

var brush_price=5;
document.write('<table border="1" align="center"><tr><th>Quantity</th><th>Price</th></tr>');
for(var counter=0; counter <= 100; counter+=10){
  document.write('<tr><td>'+counter+'</td></td>'+(counter*brush_price)+'</td></tr>');
}
document.write('</table>');

Answer 4

希望这有帮助

$brush_price = 5;
echo "<table border=\"1\" align=\"center\">";
echo "<tr><th>Quantity</th>";
echo "<th>Price</th></tr>";

for ( $count = 1, $counter=10; $count <= 10; $count++,$counter += 10) {
    echo "<tr><td>";
    echo $count;
    echo "</td><td>";
    echo $brush_price * $counter;
    echo "</td></tr>";
}
echo "</table>";

如何使用PHP打印此结果

4 个答案: