我是java的新手并且慢慢学习,所以不确定是否有明显的方法可以做到这一点,但我基本上有两个列表,我想合并在一起形成一个列表。
这个的python代码使用了一个名为zip的函数。假设我有list1 = 1,2,3,4,5
和list2= 6,7,8,9,10
..那么我想创建一个类似new_list = (1,6), (2,7), (3,8), (4,9), (5,10)
的新列表。
我发现question有类似的问题,但我不想使用外部库,而是想自己学习如何创建这个功能。
答案 0 :(得分:1)
广义算法看起来像这样(假设您想要输入N个输入列表):
public <T> List<List<T>> zip(List<T> ... lists) {
if(lists.isEmpty()) {
return Collections.<List<T>>emptyList();
}
// validate that the input lists are all the same size.
int numItems = lists[0].size();
for(int i = 1; i < lists.length; i++) {
if(lists[i].size() != numItems) {
throw new IllegalArgumentException("non-uniform-length list at index " + i);
}
}
List<List<T>> result = new ArrayList<List<T>>();
for(int i = 0; i < numItems; i++) {
// create a tuple of the i-th entries of each list
List<T> tuple = new ArrayList<T>(lists.length);
for(List<T> list : lists) {
tuple.add(list.get(i));
}
// add the tuple to the result
result.add(tuple);
}
return result;
}
答案 1 :(得分:1)
public class Blammy
{
private String left;
private String right;
public Blammy(final String left, final String right)
{
this.left = left;
this.right = right;
}
public String toString()
{
return "(" + left + ", " + right + ")";
}
}
public class Kramlish
{
public List<Blammy> mergalish(final List<String> left, final List<String> right)
{
int leftSize;
int maxSize;
int rightSize;
String leftValue;
List<Blammy> returnValue;
String rightValue;
if (left != null)
{
leftSize = left.size();
}
else
{
leftSize = 0;
}
if (right != null)
{
rightSize = right.size();
}
else
{
rightSize = 0;
}
if (leftSize > rightSize)
{
maxSize = leftSize;
}
else
{
maxSize = rightSize;
}
if (maxSize > 0)
{
returnValue = new ArrayList<Blammy>(maxSize);
for (int index = 0; index < maxSize; ++index)
{
if (index < leftSize)
{
leftValue = left.get(index);
}
else
{
leftValue = null;
}
if (index < rightSize)
{
rightValue = right.get(index);
}
else
{
rightValue = null;
}
Blammy item = new Blammy(leftValue, rightValue);
returnValue.add(item);
}
}
else
{
returnValue = new ArrayList<Blammy>();
}
return returnValue;
}
}