Question

我有5个不同的数组用于一堆练习，如下：

    const oef1:Array = ["citroen","schoen","boek"];
    const oef2:Array = ["huis","muis","jas"];
    const oef3:Array = ["boek","koek","sok"];
    const oef4:Array = ["ei","bij","bot"];
    const oef5:Array = ["vier","mier","muur"];

现在我要设置当前的游戏。我通过复制数组来实现这一点，如下所示：

var curArr:Array;
var curExc:int = 1;
curArr = ("oef" + curExc) as Array;

我无法说服flash接受字符串（“oef”+ curExc）作为数组。我该怎么做？

我已经广泛搜索了Stack Overflow，但我认为我根本不知道我正在寻找的正确术语。这是我能想到为什么我在这里找不到答案的唯一可能原因，因为我确信有人必须已经尝试过这个。如果是这种情况，请道歉，请指出正确的问题。

Answer 1

使用方括号。

curArr = this["oef" + curExc];

Answer 2

const oef1:Array = ["citroen","schoen","boek"];
const oef2:Array = ["huis","muis","jas"];
const oef3:Array = ["boek","koek","sok"];
const oef4:Array = ["ei","bij","bot"];
const oef5:Array = ["vier","mier","muur"];

const oefArrays:Array = [oef1,oef2,oef3,oef4,oef5];


var curArr:Array;
var curExc:int = 0;
curArr = oefArrays[curExc];

Answer 3

你可以制作一个二维数组，如下所示：

wrapper => [
    0 => oef1,
    1 => oef2,
    2 => oef3,
    3 => oef4,
    4 => oef5,
]

只需检索wrapper[curExc]。

度过美好的一天。

如何将字符串转换为数组

3 个答案: