序列生成器和UserType

Question

我有一个sequaance生成器

<id name="idPersistent" type="objectID" column="aa_id">
         <generator class="sequence">
            <param name="sequence">lab_seq</param>
         </generator>
      </id>  

objectID是我自己的UserType。 我收到了错误

 javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: this id generator generates long, integer, short or string

我该怎么办？

Answer 1

试试这些链接，希望这些能帮到你

• ID Generator bug in JPA implementation
• Hibernate – Many-To-Many Example – Join Table + Extra Column (Annotation)