Question

伙计们我在URL中有一个xml，我需要解析那个xml

下面的

是我的xml

这就是我解析的方式

InputStream in = new FileInputStream(file);
builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
doc = builder.parse(in, null);


            NodeList audio = doc.getElementsByTagName("point");
            int len = audio.getLength();
            Toast t = Toast.makeText(getApplicationContext(), "Length is "+len, 0);
            t.show();

            for (int i = 0; i < len; i++) {

                Node singleTerminalNode1 = audio.item(i);
                Element secondlevel = (Element)singleTerminalNode1;
                NodeList value2Nodes = (secondlevel).getElementsByTagName("file");
                String audioxml = ((Element)value2Nodes.item(0)).getAttribute("name");
                System.out.println("got the value from audioxml "+audioxml);
                Toast toast = Toast.makeText(getApplicationContext(), "Downloaded to Sdcard/varun/"+audioxml, 0);
                toast.show();

            }

但是我需要从URL解析如何使这个

Answer 1

URL url;
url = new URL("http://.....");
URLConnection ucon = url.openConnection();
ucon.connect();
url.openStream()

url.openStream()返回一个InputStream。所以用你的new FileInputStream(file);替换它应该没问题。

从URL解析xml

1 个答案: