Question

我正在开发一个简单的Intranet建议箱系统，让员工能够通过它提交他们的想法。现在，对于系统管理员，我列出所有提交的建议，并显示员工姓名，用户名，部门，建议标题，建议说明，并添加一列显示状态。对于Status列，它将显示一个DropDownList，其中包含可能的选项，如Accepted，Rejected ...等

这里我有以下问题;当管理员选择其中一个状态时，它将被更改，但不会立即更改，我不知道为什么。我怎么知道的？我在这个表下有另一个GridView，它显示了上个月提交的建议。如果管理员接受例如提交的建议之一。刷新页面后，此建议不会显示，我不知道原因。

我的ASP.NET：

<asp:GridView ID="GridView1" runat="server" AllowPaging="True" 
                        AllowSorting="True" AutoGenerateColumns="False" DataKeyNames="ID" 
                        width="950px" CssClass="mGrid"
                        AlternatingRowStyle-CssClass="alt" 
                        RowStyle-HorizontalAlign="Center" 
                        DataSourceID="SqlDataSource1" 
                        OnRowDataBound="GridView1_RowDataBound" >
            <AlternatingRowStyle BackColor="White" ForeColor="#284775" />
            <HeaderStyle Font-Bold = "true" ForeColor="Black" Height="20px"/> 
            <Columns>
                <asp:BoundField DataField="ID" HeaderText="ID" InsertVisible="False" 
                    ReadOnly="True" SortExpression="ID" />
                <asp:BoundField DataField="Title" HeaderText="Title" SortExpression="Title" />
                <asp:BoundField DataField="Description" HeaderText="Description" 
                    SortExpression="Description" />
                <asp:BoundField DataField="Name" HeaderText="Name" SortExpression="Name" />
                <asp:BoundField DataField="Username" HeaderText="Username" 
                    SortExpression="Username" />
                <asp:BoundField DataField="DivisionShortcut" HeaderText="Division" 
                    SortExpression="DivisionShortcut" />
                <asp:TemplateField HeaderText="Status">
                    <ItemTemplate>
                        <asp:DropDownList ID="DropDownList" runat="server" DataSourceID="SqlDataSource2"
                                          Font-Bold="True" ForeColor="#006666" AppendDataBoundItems="false" 
                                          DataTextField="Status" DataValueField="ID" AutoPostBack="true" 
                                          OnDataBound="DropDownList_DataBound" OnSelectedIndexChanged ="DropDownList_SelectedIndexChanged">
                        </asp:DropDownList>
                    </ItemTemplate>
                </asp:TemplateField>
            </Columns>
        </asp:GridView>
        <asp:SqlDataSource ID="SqlDataSource1" runat="server" 
            ConnectionString="<%$ ConnectionStrings:testConnectionString %>" 
            SelectCommand="SELECT     dbo.SafetySuggestionsLog.ID, dbo.SafetySuggestionsLog.Title, dbo.SafetySuggestionsLog.Description, dbo.employee.Name, dbo.SafetySuggestionsLog.Username, 
                      dbo.Divisions.DivisionShortcut
FROM         dbo.employee INNER JOIN
                      dbo.SafetySuggestionsLog ON dbo.employee.Username = dbo.SafetySuggestionsLog.Username INNER JOIN
                      dbo.Divisions ON dbo.employee.DivisionCode = dbo.Divisions.SapCode"
                      FilterExpression="[DivisionShortcut] like '{0}%'">

                      <FilterParameters>
                        <asp:ControlParameter ControlID="ddlDivision" Name="DivisionShortcut" 
                                                 PropertyName="SelectedValue" Type="String" />
                    </FilterParameters>
        </asp:SqlDataSource>

        <%--For the DropDownList--%>
        <asp:SqlDataSource ID="SqlDataSource2" runat="server"
                            ConnectionString="<%$ ConnectionStrings:testConnectionString %>" 
                            SelectCommand="SELECT * FROM [SafetySuggestionsStatus]">
        </asp:SqlDataSource>

我的守则 - 背后：

protected void DropDownList_SelectedIndexChanged(object sender, EventArgs e)
    {
        DropDownList ddl = (DropDownList)sender;
        int suggestionStatus = int.Parse(ddl.SelectedValue);
        GridViewRow row = (GridViewRow)ddl.NamingContainer;
        string strID = GridView1.DataKeys[row.RowIndex]["ID"].ToString();
        int ID = Int32.Parse(strID);
        //For inserting the status in the database
        string connString = "Data Source=localhost\\sqlexpress;Initial Catalog=psspdbTest;Integrated Security=True";
        string updateCommand = "UPDATE SafetySuggestionsLog  SET [StatusID] = @StatusID WHERE [ID] = @ID";
        using (SqlConnection conn = new SqlConnection(connString))
        {
            conn.Open();
            using (SqlCommand cmd = new SqlCommand(updateCommand, conn))
            {
                cmd.Parameters.Clear();
                cmd.Parameters.AddWithValue("@StatusID", suggestionStatus);
                cmd.Parameters.AddWithValue("@ID", ID);
                cmd.ExecuteNonQuery();
            }
            conn.Close();
        }

    }

那么如何解决此问题以便立即更新已提交建议的状态？

修改

protected void DropDownList_SelectedIndexChanged(object sender, EventArgs e)
    {
        DropDownList ddl = (DropDownList)sender;
        int suggestionStatus = int.Parse(ddl.SelectedValue);
        GridViewRow row = (GridViewRow)ddl.NamingContainer;
        string strID = GridView1.DataKeys[row.RowIndex]["ID"].ToString();
        int ID = Int32.Parse(strID);
        //For inserting the status in the database
        string connString = "Data Source=localhost\\sqlexpress;Initial Catalog=psspdbTest;Integrated Security=True";
        string updateCommand = "UPDATE SafetySuggestionsLog  SET [StatusID] = @StatusID WHERE [ID] = @ID";
        using (SqlConnection conn = new SqlConnection(connString))
        {
            conn.Open();
            using (SqlCommand cmd = new SqlCommand(updateCommand, conn))
            {
                cmd.Parameters.Clear();
                cmd.Parameters.AddWithValue("@StatusID", suggestionStatus);
                cmd.Parameters.AddWithValue("@ID", ID);
                cmd.ExecuteNonQuery();
            }
            conn.Close();
        }
        GridView1.DataBind();

    }

Answer 1

您需要在更改后再次将GridView绑定到它的DataSource。因为您使用的是声明性DataSource，所以应该使用简单的GridView1.DataBind()。

如何立即反映所提交建议状态的更新？

1 个答案: