Question

我正在以编程方式在Asp.net Gridview上创建分页。我收到错误“Microsoft JScript运行时错误：'grdAssetList_PageIndexChanged'未定义”下面是我的代码，为什么错误发生我还不明白。请帮助我。

if (ds.Tables[0].Rows.Count != 0)
    {
        setPages();
        int startRow = ((pageNumber - 1) * pageSize) + 1;
        int endRow = startRow + pageSize - 1;
        if (endRow > rowCount) endRow = rowCount;
        lblNowShowing.Text = startRow.ToString("###,##0") + " to " + endRow.ToString("###,##0") + " of " + rowCount.ToString("###,##0");
    lblPageNum.Text = "Page " + txtCurrentPageIndex.Value + " of " + pageCount.ToString(); 
    }


protected void setPages(){        
    int pageCount = Convert.ToInt16(txtPageCount.Value);
    int currentPageIndex = Convert.ToInt16(txtCurrentPageIndex.Value);
    int startPageNum = 1;
    startPageNum = currentPageIndex - 3;
    if (startPageNum < 1) startPageNum = 1;
    int endPageNum = startPageNum + 10;
    if (endPageNum > pageCount) endPageNum = pageCount;
    PlaceHolder place = PlaceHolder1;
    place.Controls.Clear();
    for (int i = startPageNum; i <= endPageNum; i++)
      {
        if (i == currentPageIndex){
            Label lblPage = new Label();
            lblPage.Text = currentPageIndex.ToString();
            place.Controls.Add(lblPage);
          } 
        else{
            HtmlAnchor btn = new HtmlAnchor();
        **btn.Attributes.Add("onclick", "grdAssetList_PageIndexChanged(" + i.ToString() + ")");** // Here i am getting error
            btn.InnerText = i.ToString();
            btn.Title = "Page " + i.ToString();
            btn.HRef = "#";
            place.Controls.Add(btn);
        }
          Label lbl = new Label();
          lbl.Text = " ";
          place.Controls.Add(lbl); }
}

on Grid allowpaging = true和OnPageIndexChanging =“grdAssetList_PageIndexChanged”

Answer 1

您的代码需要客户端功能;不是服务器端。

设置allowpaging = false

将btn定义为LinkButton（不是Anchor）

更改您加注星号的代码行。

btn.ID= "btn" + i.ToString();
btn.Click += btn_Click;

现在将函数写为

private void btn_Click(object sender, EventArgs e)
    {
        int pageno = int.Parse(((LinkButton)sender).ID.Replace("btn",""));
        LoadData(((pageno - 1) * gvPosts.PageSize) + 1, gvPosts.PageSize);
    }

在Asp.net Gridview中以编程方式获取分页错误

1 个答案: