UrlRewriteFilter错误

时间:2012-02-29 09:06:39

标签: url-rewriting servlet-filters

我正在使用maven,我将urlrewrite.xml放在源文件夹src / main / resources /下。像这样配置web.xml:

<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
<init-param>
    <param-name>confPath</param-name> 
    <param-value>classpath:urlrewrite.xml</param-value>             
</init-param>


</filter>

  <filter-mapping>
    <filter-name>UrlRewriteFilter</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>
    <dispatcher>FORWARD</dispatcher>
  </filter-mapping>

但是得到错误:org.tuckey.web.filters.urlrewrite.UrlRewriteFilter错误:无法在classpath找到urlrewrite conf文件:urlrewrite.xml。如果我把它放在默认的loc:/WEB-INF/urlrewrite.xml中。有用。但我想符合maven规范并将所有配置放在资源文件夹下。

有人可以帮助我吗?感谢。

2 个答案:

答案 0 :(得分:2)

使用此

<init-param>
    <param-name>confPath</param-name>
    <param-value>/WEB-INF/urlrewrite.xml</param-value>
</init-param>

并将urlrewrite.xml文件放在'WEB-INF'中 This article有设置说明。

答案 1 :(得分:0)

这不是世界上最干净的解决方案,但我找到了解决办法。请注意,我的应用程序是基于弹簧的:

公共类EnhancedUrlRewriteFilter扩展了UrlRewriteFilter {

private String confPath;

private final Log logger = LogFactory.getLog (getClass ());

@Override
public void init(FilterConfig filterConfig) throws ServletException {
    String confPathStr = filterConfig.getInitParameter("confPath");
    confPath = StringUtils.trim(confPathStr);
    super.init (filterConfig);
}

@Override
protected void loadUrlRewriter (FilterConfig aFilterConfig) throws ServletException {

    try {  
        configure (aFilterConfig.getServletContext ());
    }
    catch (Throwable e) {
        throw new IllegalArgumentException (e);
    }

}

private void configure (ServletContext context) throws IOException {

    ResourceLoader webApplicationContext = WebApplicationContextUtils.getWebApplicationContext (context);

    Resource resource = webApplicationContext.getResource (confPath);

    logger.debug ("Loaded urlrewrite.xml from " + resource.getFilename ());

    InputStream inputStream = resource.getInputStream();

    URL confUrl = null;

    try {
        confUrl = context.getResource(confPath);
    } catch (MalformedURLException e) {
        logger.debug(e);
    }

    String confUrlStr = null;
    if (confUrl != null) {
        confUrlStr = confUrl.toString();
    }

    if (inputStream != null) {
        Conf conf = new Conf(context, inputStream, confPath, confUrlStr, false);
        checkConf(conf);
    }
}

}

并在我的web.xml中:

<filter>
    <filter-name>UrlRewriteFilter</filter-name>
    <filter-class>EnhancedUrlRewriteFilter</filter-class>
    <init-param>
        <param-name>confPath</param-name>
        <param-value>classpath:urlrewrite.xml</param-value>
    </init-param>
    <init-param>
        <param-name>logLevel</param-name>
        <param-value>WARN</param-value>
    </init-param>
</filter>