带有DISTINCT行的SQL INNER JOIN?

时间:2012-02-28 21:25:01

标签: mysql sql sql-server

SELECT collections.title, collections.uniqueID, uploads.uniqueID as thumb 
FROM collections 
INNER JOIN uploads ON collections.uniqueID = uploads.uploadGroup 
WHERE collections.owner = @owner

在这种情况下,如果我在“uploads”中有3行具有匹配的uniqueid / uploadgroup(如在集合中的3个上传中),这会让我回到3行。

我正在寻找的是每个DISTINCT COLLECTIONS.UNIQUEID的一行 - 这可能吗?

所以当集合有

1 | title | idhere

和上传有

1 | uniqueID1 | idhere
2 | uniqueID2 | idhere
3 | uniqueID3 | idhere

我正在回来

1 | title | uniqueID1
2 | title | uniqueID2
3 | title | uniqueID3

当我想要归还的时候是

1 | title | uniqueID1

3 个答案:

答案 0 :(得分:4)

如果您需要上传表格中的简单不同列表,那么您可以这样做:

SELECT collections.title, collections.uniqueID, uploads.uniqueID as thumb 
FROM collections 
INNER JOIN (SELECT DISTINCT uniqueID FROM uploads) uploads ON collections.uniqueID = uploads.uploadGroup 
WHERE collections.owner = @owner

答案 1 :(得分:3)

这是一种方法(仅限sql server):

SELECT collections.title, collections.uniqueID, uploads.uniqueID as thumb 
FROM collections
CROSS APPLY (
    SELECT TOP 1 *
    FROM uploads
    WHERE collections.uniqueID = uploads.uploadGroup
    ORDER BY uploads.uniqueID -- not required, can be changed to any column you want
) uploads

答案 2 :(得分:2)

SELECT collections.title, collections.uniqueID, min(uploads.uniqueID) as thumb 
FROM collections 
JOIN uploads ON collections.uniqueID = uploads.uploadGroup 
WHERE collections.owner = @owner
GROUP BY collections.title, collections.uniqueID