Question

我似乎无法从钥匙串中获取值，因为它始终返回ItemNotFound。我正在使用的代码如下：

private static Guid GetID()
    {           
        Guid returnGuid = Guid.Empty;
        SecStatusCode code;
        SecRecord queryRec = new SecRecord (SecKind.GenericPassword) { Service = KEYCHAIN_SERVICE, Label = KEYCHAIN_SERVICE, Account = KEYCHAIN_ACCOUNT };
        queryRec = SecKeyChain.QueryAsRecord (queryRec, out code);

        if (code == SecStatusCode.Success && queryRec != null && queryRec.Generic != null )
        {
            returnGuid = new Guid(NSString.FromData(queryRec.Generic, NSStringEncoding.UTF8));
        }

        return returnGuid;

    }

当我尝试设置值时，它返回DuplicateItem并使用以下代码：

private static SecStatusCode SetID (Guid setID)
    {           
        SecStatusCode code = SecKeyChain.Add (new SecRecord (SecKind.GenericPassword) {
            Service = KEYCHAIN_SERVICE,
            Label = KEYCHAIN_SERVICE,
            Account = KEYCHAIN_ACCOUNT,
            Generic = NSData.FromString(Convert.ToString(setID), NSStringEncoding.UTF8),
            Accessible = SecAccessible.Always
        } );

        return code;
    }

任何帮助都会很棒！

Answer 1

我将您的代码复制粘贴到Touch.Unit解决方案中，它可以在模拟器和设备上运行。

    [Test]
    public void CheckId ()
    {
        Guid g = Guid.NewGuid ();
        SetID (g);
        Assert.That (g, Is.EqualTo (GetID ()), "same guid");
    }

我唯一要改变的是你的KEYCHAIN_*常量字符串，我保持相同的值（即只添加引号）。

现在，如果您执行代码第二次时间，您将收到DuplicateItem错误代码，因为SetID正在尝试设置相同的项再次当你查询Guid时，你会得到第一个 - 导致错误。

您有两个选择，删除现有项目或更新它。例如。删除现有项目......

    static SecStatusCode SetID (Guid setID)
    {
        SecRecord queryRec = new SecRecord (SecKind.GenericPassword) { 
            Service = "KEYCHAIN_SERVICE", 
            Label = "KEYCHAIN_SERVICE", 
            Account = "KEYCHAIN_ACCOUNT" 
        };
        var record = new SecRecord (SecKind.GenericPassword) {
            Service = "KEYCHAIN_SERVICE",
            Label = "KEYCHAIN_SERVICE",
            Account = "KEYCHAIN_ACCOUNT",
            Generic = NSData.FromString (Convert.ToString (setID), NSStringEncoding.UTF8),
            Accessible = SecAccessible.Always
        };
        SecStatusCode code = SecKeyChain.Add (record);
        if (code == SecStatusCode.DuplicateItem) {
            code = SecKeyChain.Remove (queryRec);
            if (code == SecStatusCode.Success)
                code = SecKeyChain.Add (record);
        }
        return code;
    }

注意：测试时我从未得到ItemNotFound。

MonoTouch无法获得现有钥匙串项的价值

1 个答案: