Question

当前代码检索所有信息，显示地图上的所有标记，如果单击标记，则infowindow呈现显示其内容。我想做的是我想在此实现方向。如何在我的代码中添加路线以便它还可以添加路线？这就是我想要实现的：

要实施的内容：

var request = {
  origin: start,//it will be my first row(lat and lon)
  destination: end,//it will be my lastrow(lat and lon)
  waypoints: waypts, // it will be all lat and lon between first and last
  optimizeWaypoints: true,
  travelMode: google.maps.TravelMode.DRIVING
 };

 directionsService.route(request, function(response, status){
if (status == google.maps.DirectionsStatus.OK){
    directionsDisplay.setDirections(response);
}
 });

我想要实现上述功能的当前代码意味着谷歌地图指示：

已实施：

$("#directions").click(function(){
    var lat_from_ip   = $("#hidden_lat").val();
    var lon_from_ip   = $("#hidden_lon").val();

    var latlng = new google.maps.LatLng(lat_from_ip, lon_from_ip);
    var options = {zoom: 4, center: latlng, mapTypeId: google.maps.MapTypeId.ROADMAP};
    var map = new google.maps.Map(document.getElementById('map'), options);

    $.ajax({type: "GET",
    dataType: 'json',
    url: url +'//abc/my_page.php',
    success: function(response){
         var total=response.length;
         var data_array,name,type,address,lat,lon,infowindow;
         var infowindow = new google.maps.InfoWindow();  

       for(var i=0; i < total; i++) 
       {
            data_array=response[i];
            name=data_array['name'];
            address=data_array['address'];
            notes=data_array['notes'];
            lat=data_array['lat'];
            lon=data_array['lon'];

        var propPos = new google.maps.LatLng(lat,lon);

            propMarker = new google.maps.Marker({
                    position: propPos,
                    map: map,
                    icon: icon,
                    zIndex: 3});

var contentString = "<div>"+name+"<br/><label class='label'>Location :</label> "+address+"<br/><label class='label'>Notes :</label> "+notes + "</div>"; 

              function bindInfoWindow(marker, map, infowindow, html) {
         google.maps.event.addListener(marker, 'click', function() {
               infowindow.setContent(html);
               infowindow.open(map, marker);
                });
                 }

             bindInfoWindow(propMarker, map, infowindow, contentString);

     }   //end of for loop
          } //end of for success
    }); //end of for $.ajax
    return;


    });

Answer 1

绘制路线的功能，只要您想要显示路线就可以调用它。您可以将一些变量传递给它，并在里面使用它们来决定哪些标记将是开始，结束和路径。

function calcRoute() {
    var startpt = yourstartlatlng;
    var endpt = yourendlatlng;
    var waypts = [] //your waypts array, if there are more than 1 point
    var request = {
        origin:startpt, 
        destination:endpt,
        waypoints: waypts,
        travelMode: google.maps.DirectionsTravelMode.DRIVING
    };
    directionsService.route(request, function(response, status) {
      if (status == google.maps.DirectionsStatus.OK) {
        directionsDisplay.setDirections(response);
      }
    });
  }

此处的示例：Google Maps Api

修改当你在php中有一个名为waypts的数组，并且你想在javascript中拥有这些值时，你需要将它们传递给java。它有点混乱，但这是我知道的唯一方式：

<script type="text/javascript"> var waypts = []; <?php $waypts= array(1, 2, 3, 4); //<-- your array, can be called like that, or just have values inside already for($i = 0; $i < sizeof($waypts); $i++){ ?> waypts[<?php echo $i; ?>] = <?php echo $waypts[$i]; ?>; //php is interpreted before java, when site will load, these values will be inside java "waypts" variable. <?php } ?> alert(""+waypts[1]); </script>

该代码将把你的php变量/数组放入java数组中（警告只是检查它是否完成了这项工作，你可以删除它，一旦你理解了代码）。然后您可以根据需要使用这些变量。 PHP的解释早于java，所以在站点代码中你会得到waypts [0] = 1; cuz php代码已经被数组中的值替换。

Answer 2

这是如何将php数组转换为js数组

例如你有php数组

<?php
$my_array = array("a","b","c");
 ?>

现在在js中这样做

<script>
var jsArray = ["<?php echo join("\", \"", $my_array); ?>"];
alert(jsArray);

在您的域名中就像这样。假设你有像这样的php数组。 $ data; //这是你的php数组

Array
(
[0] => Array
    (
        [lat] => 31.453795
        [lon] => 74.388497
    )

[1] => Array
    (
        [lat] => 31.454387
        [lon] => 74.388541
    )

[2] => Array
    (
        [lat] => 31.453795
        [lon] => 74.388497
    )
   .
   .
   .
 )

在js中这样做

var waypts = [];
<?php
 foreach($data as  $key => $value){
if(($key == '0') || ($key == count($data)-1)){
    continue;
    }?>
 waypts.push({location:  new google.maps.LatLng(<?php echo $data[$key]['lat'] ?>, <?php echo $data[$key]['lon'] ?>)});
<?php }?>

如何在谷歌地图中添加谷歌方向

2 个答案: