我正在使用Imgur api从我的webapp上传图片。如何使用C#Asp.net
从此XML字符串的标记中提取URL <upload>
<image>
<name />
<title />
<caption />
<hash>MkUDH</hash>
<deletehash>kP5lIWWU0vDqrO1</deletehash>
<datetime>2012-02-28 11:47:25</datetime>
<type>image/jpeg</type>
<animated>false</animated>
<width>640</width>
<height>480</height>
<size>173578</size>
<views>0</views>
<bandwidth>0</bandwidth>
</image>
<links>
<original>http://i.imgur.com/MkUDH.jpg</original>
<imgur_page>http://imgur.com/MkUDH</imgur_page>
<delete_page>http://imgur.com/delete/kP5lIWWU0vDqrO1</delete_page>
<small_square>http://i.imgur.com/MkUDHs.jpg</small_square>
<large_thumbnail>http://i.imgur.com/MkUDHl.jpg</large_thumbnail>
</links>
</upload>
答案 0 :(得分:1)
您可以尝试Linq Xml
读取xml文档并提取元素值。
XDocument doc = XDocument.Load(file);
var result = doc.Root.Element("links").Element("original").Value;
答案 1 :(得分:0)
XmlDocument xml = new XmlDocument();
xml.LoadXml(myXmlString); // your XML String
XmlNodeList xnList = xml.SelectNodes("/upload/links");
foreach (XmlNode xn in xnList)
{
string original= xn["original"].InnerText;
string imgur_page = xn["imgur_page"].InnerText;
string delete_page = xn["delete_page"].InnerText;
string small_square = xn["small_square"].InnerText;
string large_thumbnail= xn["large_thumbnail"].InnerText;
}
答案 2 :(得分:0)
var url = Regex.Replace(s, @".*original\>(.*)\<\/original\>.*", "$1")
输出:
http://i.imgur.com/MkUDH.jpg