以下是我的查询。这是正确的吗?
SQL> select case when value in (1000) then null
2 when user in ('ABC') then user
3 when area in ('DENVER') then
4 if value = 2000 then 'Service1'
5 else value = 3000 then 'Service2'
6 end if
7 else null
8 end as num_code from service_usoc_ref;
if prin = 2000 then 'Omaha'
*
ERROR at line 4:
ORA-00905: missing keyword
请帮帮我。
答案 0 :(得分:9)
你可以放另一个案例或使用解码(如@madhu建议的那样):
select case
when value in (1000) then null
when user in ('ABC') then user
when area in ('DENVER') then
case when value = 2000 then 'Service1'
when value = 3000 then 'Service2'
end
else null
end as num_code
from service_usoc_ref;
答案 1 :(得分:3)
这可以帮到你
select case when value in (1000) then null
when user in ('ABC') then user
when area in ('DENVER') then
decode( value, 2000 , 'Service1',3000 , 'Service2', NULL) num_code
from service_usoc_ref;