我编写了一个转换器类,它接受HttpServletRequest并将其转换为另一种类型,该类型保存来自servlet请求的InputStream指针。 (这个想法是从请求处理中抽象出传输传输协议,所以我也可以从FTP编写类似的转换器。)
现在我正在尝试为此编写单元测试,但我遇到了问题。我已经设法找出正确的样板来创建有效的Multipart HTTP请求(使用Spring类MockMultipartHttpServletRequest和MockMultipartFile),但现在我在initialize()
类的UploadRequest
方法中得到了NullPointerException。我猜测问题是,MockMultipartHttpServletRequest中的流不能正确初始化,但我无法弄清楚我应该做些什么不同。
任何建议都会被感激地接受!
这是堆栈跟踪:
java.lang.NullPointerException
at org.apache.commons.fileupload.MultipartStream$ItemInputStream.makeAvailable(MultipartStream.java:976)
at org.apache.commons.fileupload.MultipartStream$ItemInputStream.read(MultipartStream.java:886)
at java.io.InputStream.read(InputStream.java:82)
at org.apache.commons.fileupload.util.Streams.copy(Streams.java:96)
at org.apache.commons.fileupload.util.Streams.copy(Streams.java:66)
at org.apache.commons.fileupload.MultipartStream.readBodyData(MultipartStream.java:592)
at org.apache.commons.fileupload.MultipartStream.discardBodyData(MultipartStream.java:618)
at org.apache.commons.fileupload.MultipartStream.skipPreamble(MultipartStream.java:637)
at org.apache.commons.fileupload.FileUploadBase$FileItemIteratorImpl.findNextItem(FileUploadBase.java:984)
at org.apache.commons.fileupload.FileUploadBase$FileItemIteratorImpl.<init>(FileUploadBase.java:965)
at org.apache.commons.fileupload.FileUploadBase.getItemIterator(FileUploadBase.java:331)
at org.apache.commons.fileupload.servlet.ServletFileUpload.getItemIterator(ServletFileUpload.java:148)
at com.ooyala.UploadRequest.initialize(UploadRequest.java:51)
at com.ooyala.UploadRequestTest.testCreateFromServletRequest(UploadRequestTest.java:57)
这是我的变压器类的缩写版本:
public class UploadRequest {
private Map<String, String> params;
private InputStream strIn;
private Logger Log = Logger.getLogger(UploadRequest.class.getName());
public UploadRequest()
{
params = new HashMap<String, String>();
}
public void initialize(HttpServletRequest sRequest,
ServletFileUpload upload)
throws IOException, FileUploadException
{
Enumeration<String> paramNames = sRequest.getParameterNames();
while (paramNames.hasMoreElements()) {
String pName = paramNames.nextElement();
params.put(pName, sRequest.getParameter(pName));
}
params.put("request_uri", sRequest.getRequestURI());
FileItemIterator iter = upload.getItemIterator(sRequest);
while (iter.hasNext()) {
FileItemStream item = iter.next();
try {
if (!item.isFormField()) {
// Skip form fields
params.put("original_file_name", item.getName());
strIn = item.openStream();
}
} catch (IOException ex) {
Log.severe("File uploading exception: " + ex.getMessage());
throw ex;
}
}
}
这是单元测试:
import org.springframework.mock.web.MockMultipartHttpServletRequest;
import org.springframework.mock.web.MockMultipartFile;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
// etc.... other imports
@RunWith(JMock.class)
public class UploadRequestTest {
private UploadRequest upRequest;
@Before
public void setUp()
{
context.setImposteriser(ClassImposteriser.INSTANCE);
upRequest = new UploadRequest();
}
@Test
public void testCreateFromServletRequest()
throws IOException, FileUploadException
{
String text_contents = "hello world";
MockMultipartHttpServletRequest sRequest =
new MockMultipartHttpServletRequest();
sRequest.setMethod("POST");
String boundary = generateBoundary();
String contentType = "multipart/form-data; boundary="+boundary;
sRequest.setContentType(contentType);
sRequest.setRequestURI("/foo");
sRequest.addParameter("test_param","test_value");
sRequest.addFile(
new MockMultipartFile("file1","test_upload.txt","text/plain",
text_contents.getBytes()));
ServletFileUpload upload = new ServletFileUpload();
assertTrue(upload.isMultipartContent(sRequest));
upRequest.initialize(sRequest, upload);
}
}
答案 0 :(得分:1)
我有同样的问题,我用谷歌搜索但没有回答。我插入了库中的源代码,你需要发送内容,无论如何。库可能需要检查skip方法中是否为null
MockMultipartHttpServletRequest request
request.setContent("whatever".getBytes());
在这里发布给其他人
答案 1 :(得分:1)
生成内容如下
MockMultipartHttpServletRequest request =
this.generateMockMultiPartHttpServletRequest(true);
MockMultipartFile mockMultipartFile = null;
try {
request.setContentType("multipart/form-data; boundary=-----1234");
request.setCharacterEncoding("text/plain");
String endline = "\r\n";
String bondary = "-----1234";
String textFile = this.encodeTextFile("-----1234", "\r\n", "file","test.csv",
"text/UTF-8", FileUtils.readFileToString((new File(csvFilePath)), "UTF-8"));
StringBuilder content = new StringBuilder(textFile.toString());
content.append(endline);
content.append(endline);
content.append(endline);
content.append("--");
content.append(bondary);
content.append("--");
content.append(endline);
request.setContent(content.toString().getBytes());
request.setMethod("POST");
mockMultipartFile = new MockMultipartFile("file",
FileUtils.readFileToByteArray(new File(csvFilePath)));
} catch (Exception e1) {
e1.printStackTrace();
}
request.addFile(mockMultipartFile);
编码文本的功能
private String encodeTextFile(String bondary, String endline, String name,
String filename, String contentType, String content) {
final StringBuilder sb = new StringBuilder(64);
sb.append(endline);
sb.append("--");
sb.append(bondary);
sb.append(endline);
sb.append("Content-Disposition: form-data; name=\"");
sb.append(name);
sb.append("\"; filename=\"");
sb.append(filename);
sb.append("\"");
sb.append(endline);
sb.append("Content-Type: ");
sb.append(contentType);
sb.append(endline);
sb.append(endline);
sb.append(content);
return sb.toString();
}
答案 2 :(得分:1)
我经历了同样的问题,经过搜索很多我得到了这篇帖子,其中我回答了解决我问题的代码。
Shriprasad的解决方案适用于文本文件。但我在二进制文件方面遇到了一些问题。