Question

可能重复：
Dismiss a custom dialog?

我有一个自定义对话框，对话框的布局文件包含一个 id “submit_btn”的按钮。

在java代码中，我setOnClickListener到对话框的submit_btn按钮：

View view = layoutInflater.inflate(R.layout.info_dialog, null);

AlertDialog infoDialog = new AlertDialog.Builder(MyActivity.this)
                                           .setView(view)        
                                           .create();
infoDialog.show();  

Button submitBtn = (Button) view.findViewById(R.id.submit_btn);

submitBtn.setOnClickListener(new OnClickListener() {

          public void onClick(View v) {
       //ERROR: Cannot refer to a non-final variable infoDialog inside an inner class defined in a different method

                     infoDialog.dismiss();
       }
});

然后，当我调用infoDialog.dismiss();时，Eclipse会引发错误，该错误会引发Cannot refer to a non-final variable infoDialog inside an inner class defined in a different method。如何根据我的代码摆脱这个问题？

Answer 1

使用

final AlertDialog infoDialog = new AlertDialog.Builder(MyActivity.this)
                                       .setView(view)        
                                       .create();

Answer 2

你能做到这一点......

final AlertDialog infoDialog = new AlertDialog.Builder(MyActivity.this)
                                           .setView(view)        
                                           .create();

// just add final to that line.

或者您可以增加infoDialog的范围。

public class YourActivity {

    private AlertDialog mInfoDialog;

    private YourMethod() {
        View view = layoutInflater.inflate(R.layout.info_dialog, null);

        mInfoDialog = new AlertDialog.Builder(MyActivity.this)
                                           .setView(view)        
                                           .create();
        mInfoDialog.show();  

        Button submitBtn = (Button) view.findViewById(R.id.submit_btn);

        submitBtn.setOnClickListener(new OnClickListener() {

            public void onClick(View v) {
                mInfoDialog.dismiss();
            }
        });
    }
}

Answer 3

AlertDialog infoDialog = new AlertDialog.Builder(MyActivity.this)
                                         .setView(view)
                                         .setPositiveButton("ok", /*OnClickListenerGoesHere*/)    
                                         .create();

将解决您的问题，并在单击按钮时关闭对话框。

Answer 4

将infoDialog设为类的私有成员，或者将final关键字添加为 final AlertDialog infoDialog = new AlertDialog（...）

setOnClickListener在我的情况下引发错误

4 个答案: