Question

我有一个Parent / Child类层次结构，其中Parent抽象地声明了一个字符串属性，而Child类实现了它：

abstract class Parent
{
   public abstract string Value { get; }
}

class Child : Parent
{
   public override string Value { get { return null; } }
}

当我使用显式（或隐式）使用Child类的表达式时，我希望Expressions的MemberInfo的DeclaringType为'Child'，而是它是Parent：

Child child = new Child();
Expression<Func<string>> expression = (() => child.Value);
MemberInfo memberInfo = expression.GetMemberInfo();
Assert.AreEqual(typeof(Child), memberInfo.DeclaringType); // FAILS!

断言失败，因为DeclaringType是Parent。

在声明我的表达或使用它来揭示Child类型的实际用途时，我能做些什么吗？

注意：上面的GetMemberInfo（）作为扩展方法（我甚至忘记了我们写过这个！）：

public static class TypeExtensions
{
    /// <summary>
    /// Gets the member info represented by an expression.
    /// </summary>
    /// <param name="expression">The member expression.</param>
    /// <returns>The member info represeted by the expression.</returns>
    public static MemberInfo GetMemberInfo(this Expression expression)
    {
        var lambda = (LambdaExpression)expression;

        MemberExpression memberExpression;
        if (lambda.Body is UnaryExpression)
        {
            var unaryExpression = (UnaryExpression)lambda.Body;
            memberExpression = (MemberExpression)unaryExpression.Operand;
        }
        else memberExpression = (MemberExpression)lambda.Body;

        return memberExpression.Member;
    }
}

Answer 1

否 - 这是C＃编译器发出的内容的准确表示。在查找成员时，有效地忽略了覆盖 - 编译器只关心最初声明成员的类型。您可以通过编译代码然后查看IL来自行查看。这个方法：

static void Main()
{
    Child c = new Child();
    string x = c.Value;
}

被编译到这个IL中：

IL_0000:  nop
IL_0001:  newobj     instance void Child::.ctor()
IL_0006:  stloc.0
IL_0007:  ldloc.0
IL_0008:  callvirt   instance string Parent::get_Value()
IL_000d:  stloc.1
IL_000e:  ret

一点琐事：VB编译器不会以相同的方式工作，所以这个方法：

Public Shared Sub Main(Args As String())
    Dim x As Child = New Child()
    Dim y As String = x.Value
End Sub

编译为：

IL_0000:  newobj     instance void [lib]Child::.ctor()
IL_0005:  stloc.0
IL_0006:  ldloc.0
IL_0007:  callvirt   instance string [lib]Child::get_Value()
IL_000c:  stloc.1
IL_000d:  ret

Answer 2

基于来自@JonSkeet和@CodeInChaos的信息，我的解决方案不是纯粹看表达式中的PropertyInfo，而是看看MemberExpression成员组件的类型：

/// <summary>
/// Extracts the PropertyInfo for the propertybeing accessed in the given expression.
/// </summary>
/// <remarks>
/// If possible, the actual owning type of the property is used, rather than the declaring class (so if "x" in "() => x.Foo" is a subclass overriding "Foo", then x's PropertyInfo for "Foo" is returned rather than the declaring base class's PropertyInfo for "Foo").
/// </remarks>
/// <typeparam name="T"></typeparam>
/// <param name="propertyExpression"></param>
/// <returns></returns>
internal static PropertyInfo ExtractPropertyInfo<T>(Expression<Func<T>> propertyExpression)
{
    if (propertyExpression == null)
    {
        throw new ArgumentNullException("propertyExpression");
    }

    var memberExpression = propertyExpression.Body as MemberExpression;
    if (memberExpression == null)
    {
        throw new ArgumentException(string.Format("Expression not a MemberExpresssion: {0}", propertyExpression), "propertyExpression");
    }

    var property = memberExpression.Member as PropertyInfo;
    if (property == null)
    {
        throw new ArgumentException(string.Format("Expression not a Property: {0}", propertyExpression), "propertyExpression");
    }

    var getMethod = property.GetGetMethod(true);
    if (getMethod.IsStatic)
    {
        throw new ArgumentException(string.Format("Expression cannot be static: {0}", propertyExpression), "propertyExpression");
    }

    Type realType = memberExpression.Expression.Type;
    if(realType == null) throw new ArgumentException(string.Format("Expression has no DeclaringType: {0}", propertyExpression), "propertyExpression");

    return realType.GetProperty(property.Name);
}

Answer 3

如果您不想使用静态类型的方法，而是需要最新的覆盖，则可以。我没有测试，但类似于以下的东西应该做的工作：

public bool FindOverride(MethodInfo baseMethod, Type type)
{
    if(baseMethod==null)
      throw new ArgumentNullException("baseMethod");
    if(type==null)
      throw new ArgumentNullException("type");
    if(!type.IsSubclassOf(baseMethod.ReflectedType))
        throw new ArgumentException(string.Format("Type must be subtype of {0}",baseMethod.DeclaringType));
    while(true)
    {
        var methods=type.GetMethods(BindingFlags.Instance|
                                    BindingFlags.DeclaredOnly|
                                    BindingFlags.Public|
                                    BindingFlags.NonPublic);
        var method=methods.FirstOrDefault(m=>m.GetBaseDefinition()==baseMethod))
        if(method!=null)
          return method;
        type=type.BaseType;
    }
}

将MemberInfo作为第一个参数传递，将对象的运行时类型作为第二个参数传递。请注意，这可能很慢，因此您可能需要添加一些缓存。

如何让孩子从表达式中声明类型？

3 个答案: