我在网上发现了许多“转换器”,但是我找不到任何可以轻松实现的源代码。我想知道是否有人会如此友善地向我提供建议,甚至为我提供代码来为我完成这项任务。我正在尝试转换为XML,因此解析起来会更容易。
我正在尝试转换此内容(Cognos XML Schema)...
<?xml version="1.0" encoding="utf-8" ?>
- <dataset xmlns="http://developer.cognos.com/schemas/xmldata/1/" xmlns:xs="http://www.w3.org/2001/XMLSchema-instance">
- <!--
<dataset
xmlns="http://developer.cognos.com/schemas/xmldata/1/"
xmlns:xs="http://www.w3.org/2001/XMLSchema-instance"
xs:schemaLocation="http://developer.cognos.com/schemas/xmldata/1/ xmldata.xsd"
>
-->
- <metadata>
<item name="ROOT_NODE_ID" type="xs:decimal" precision="38" />
<item name="LEVEL1_ID" type="xs:string" length="2002" />
<item name="LEVEL1_NAME" type="xs:string" length="512" />
<item name="LEVEL2_ID" type="xs:string" length="2002" />
<item name="LEVEL2_NAME" type="xs:string" length="512" />
<item name="LEVEL3_ID" type="xs:string" length="2002" />
<item name="LEVEL3_NAME" type="xs:string" length="512" />
<item name="LEVEL4_ID" type="xs:string" length="2002" />
<item name="LEVEL4_NAME" type="xs:string" length="512" />
<item name="LEVEL5_ID" type="xs:string" length="2002" />
<item name="LEVEL5_NAME" type="xs:string" length="512" />
<item name="LEVEL6_ID" type="xs:string" length="2002" />
<item name="LEVEL6_NAME" type="xs:string" length="512" />
<item name="LEVEL7_ID" type="xs:string" length="2002" />
<item name="LEVEL7_NAME" type="xs:string" length="512" />
<item name="LEVEL8_ID" type="xs:string" length="2002" />
<item name="LEVEL8_NAME" type="xs:string" length="512" />
<item name="LEVEL9_ID" type="xs:string" length="2002" />
<item name="LEVEL9_NAME" type="xs:string" length="512" />
<item name="LEVEL10_ID" type="xs:string" length="2002" />
<item name="LEVEL10_NAME" type="xs:string" length="512" />
</metadata>
- <data>
- <row>
<value>5</value>
<value>5</value>
<value>Global Root</value>
<value>41</value>
<value>Company</value>
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
</row>
- <row>
<value>5</value>
<value>5</value>
<value>Global Root</value>
<value>41</value>
<value>Company</value>
<value>101590</value>
<value>Customer</value>
<value>101591</value>
<value>Customer -All Sites</value>
<value>125083</value>
<value>Site 1</value>
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
<value xs:nil="true" />
</row>
</data>
</dataset>
到此(XML)....
<?xml version="1.0" encoding="UTF-8"?>
<rows>
<row>
<ROOT_NODE_ID>5</ROOT_NODE_ID>
<LEVEL1_ID>5</LEVEL1_ID>
<LEVEL1_NAME>Global Root</LEVEL1_NAME>
<LEVEL2_ID>41</LEVEL2_ID>
<LEVEL2_NAME>Company</LEVEL2_NAME>
<LEVEL3_ID></LEVEL3_ID>
<LEVEL3_NAME></LEVEL3_NAME>
<LEVEL4_ID></LEVEL4_ID>
<LEVEL4_NAME></LEVEL4_NAME>
<LEVEL5_ID></LEVEL5_ID>
<LEVEL5_NAME></LEVEL5_NAME>
<LEVEL6_ID></LEVEL6_ID>
<LEVEL6_NAME></LEVEL6_NAME>
<LEVEL7_ID></LEVEL7_ID>
<LEVEL7_NAME></LEVEL7_NAME>
<LEVEL8_ID></LEVEL8_ID>
<LEVEL8_NAME></LEVEL8_NAME>
<LEVEL9_ID></LEVEL9_ID>
<LEVEL9_NAME></LEVEL9_NAME>
<LEVEL10_ID></LEVEL10_ID>
<LEVEL10_NAME></LEVEL10_NAME>
</row>
<row>
<ROOT_NODE_ID>5</ROOT_NODE_ID>
<LEVEL1_ID>5</LEVEL1_ID>
<LEVEL1_NAME>Global Root</LEVEL1_NAME>
<LEVEL2_ID>41</LEVEL2_ID>
<LEVEL2_NAME>Company</LEVEL2_NAME>
<LEVEL3_ID>101590</LEVEL3_ID>
<LEVEL3_NAME>Customer</LEVEL3_NAME>
<LEVEL4_ID>101591</LEVEL4_ID>
<LEVEL4_NAME>Customer -All Sites</LEVEL4_NAME>
<LEVEL5_ID>125083</LEVEL5_ID>
<LEVEL5_NAME>Site 1</LEVEL5_NAME>
<LEVEL6_ID></LEVEL6_ID>
<LEVEL6_NAME></LEVEL6_NAME>
<LEVEL7_ID></LEVEL7_ID>
<LEVEL7_NAME></LEVEL7_NAME>
<LEVEL8_ID></LEVEL8_ID>
<LEVEL8_NAME></LEVEL8_NAME>
<LEVEL9_ID></LEVEL9_ID>
<LEVEL9_NAME></LEVEL9_NAME>
<LEVEL10_ID></LEVEL10_ID>
<LEVEL10_NAME></LEVEL10_NAME>
</row>
</rows>
答案 0 :(得分:0)
此Xslt从任意Cognos报告中剥离任何模式元数据 - Xml输出方法 - 并创建从元数据中提取名称的结果元素:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns="http://tempuri.org/" xmlns:cog="http://developer.cognos.com/schemas/xmldata/1/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:template match="//comment()" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="cog:dataset">
<rows>
<xsl:apply-templates />
</rows>
</xsl:template>
<xsl:template match="cog:metadata">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="cog:item">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="@name | @type | @length | @precision" />
<xsl:template match="cog:data">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="cog:row">
<row>
<xsl:apply-templates />
</row>
</xsl:template>
<xsl:template match="cog:value">
<xsl:variable name="currentposition" select="count(./preceding-sibling::cog:value)+1" />
<xsl:variable name="currentname" select="//cog:metadata/cog:item[$currentposition]/@name" />
<xsl:element name="{$currentname}">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
如果你想让Cognos应用服务器端转换,你必须选择 XHTML 输出方法,这将使转换更容易一些每个字段都将带有实际名称,而不是 value 。