XQuery脚本需要显示xml文件中的所有公司名称和联系人姓名。
这就是我所拥有的: -
for $x in doc("Customers.xml")/dataroot/Customers
return $x/CompanyName $x/ContactName
示例xml
<dataroot>
<Customers>
<CustomerID>ALFKI</CustomerID>
<CompanyName>Alfreds Futterkiste</CompanyName>
<ContactName>Maria Anders</ContactName>
<ContactTitle>Sales Representative</ContactTitle>
<Address>Obere Str. 57</Address>
<City>Berlin</City>
<PostalCode>12209</PostalCode>
<Country>Germany</Country>
<Phone>030-0074321</Phone>
<Fax>030-0076545</Fax>
</Customers>
<Customers>
<CustomerID>ANATR</CustomerID>
<CompanyName>Ana Trujillo Emparedados y helados</CompanyName>
<ContactName>Ana Trujillo</ContactName>
<ContactTitle>Owner</ContactTitle>
<Address>Avda. de la Constitución 2222</Address>
<City>México D.F.</City>
<PostalCode>05021</PostalCode>
<Country>Mexico</Country>
<Phone>(5) 555-4729</Phone>
<Fax>(5) 555-3745</Fax>
</Customers>
<Customers>
<CustomerID>ANTON</CustomerID>
<CompanyName>Antonio Moreno Taquería</CompanyName>
<ContactName>Antonio Moreno</ContactName>
<ContactTitle>Owner</ContactTitle>
<Address>Mataderos 2312</Address>
<City>México D.F.</City>
<PostalCode>05023</PostalCode>
<Country>Mexico</Country>
<Phone>(5) 555-3932</Phone>
</Customers>
<Customers>
<CustomerID>AROUT</CustomerID>
<CompanyName>Around the Horn</CompanyName>
<ContactName>Thomas Hardy</ContactName>
<ContactTitle>Sales Representative</ContactTitle>
<Address>120 Hanover Sq.</Address>
<City>London</City>
<PostalCode>WA1 1DP</PostalCode>
<Country>UK</Country>
<Phone>(171) 555-7788</Phone>
<Fax>(171) 555-6750</Fax>
</Customers>
<Customers>
<CustomerID>BERGS</CustomerID>
<CompanyName>Berglunds snabbköp</CompanyName>
<ContactName>Christina Berglund</ContactName>
<ContactTitle>Order Administrator</ContactTitle>
<Address>Berguvsvägen 8</Address>
<City>Luleå</City>
<PostalCode>S-958 22</PostalCode>
<Country>Sweden</Country>
<Phone>0921-12 34 65</Phone>
<Fax>0921-12 34 67</Fax>
</Customers>
我想仅返回CompanyName和ContactName。这些必须能够轻松转换为表格格式,因此它以列
结构化答案 0 :(得分:1)
XQuery的基本数据模型是sequence,而不是表格或relation。这也适用于XQuery的result
。因此,默认情况下,您将收到return
子句返回的序列。默认情况下不返回“列”或“表”。如果你需要一个不同的或“更深层次结构”的返回结构,那么你必须自己添加它。
获取结构化结果的最简单方法是创建XML输出。因此,大多数XQuery教程都以返回XML开始,而不是纯文本或其他任何内容。
如果您需要“表格结构”作为输出,则有不同的选项:
要输出XML,您可以使用以下内容:
xquery version "1.0";
<table>
{
for $cust in fn:doc("Customers.xml")/dataroot/Customers
return
<row>
{
$cust/CompanyName, $cust/ContactName
}
</row>
}
</table>
它会返回类似的内容:
<table>
<row>
<CompanyName>Alfreds Futterkiste</CompanyName>
<ContactName>Maria Anders</ContactName>
</row>
<row>
<CompanyName>Ana Trujillo Emparedados y helados</CompanyName>
<ContactName>Ana Trujillo</ContactName>
</row>
<row>
<CompanyName>Antonio Moreno Taquería</CompanyName>
<ContactName>Antonio Moreno</ContactName>
</row>
<row>
<CompanyName>Around the Horn</CompanyName>
<ContactName>Thomas Hardy</ContactName>
</row>
<row>
<CompanyName>Berglunds snabbköp</CompanyName>
<ContactName>Christina Berglund</ContactName>
</row>
</table>
对于CSV输出(更准确地说:一系列类似CSV的字符串),您可以使用
xquery version "1.0";
for $cust in fn:doc("Customers.xml")/dataroot/Customers
return
concat('"', $cust/CompanyName, '"', ',', '"', $cust/ContactName, '"')
获得类似
的内容"Alfreds Futterkiste","Maria Anders"
"Ana Trujillo Emparedados y helados","Ana Trujillo"
"Antonio Moreno Taquería","Antonio Moreno"
"Around the Horn","Thomas Hardy"
"Berglunds snabbköp","Christina Berglund"
编辑:一些XQuery处理器也提供内置的CSV序列化。例如,Zorba XQuery processor包括module to parse / serialize CSV。