我正在尝试使用Google专利创建所有专利信息的数据库。到目前为止,我的大部分工作都是在Python to parse non-standard XML file中使用MattH的这个非常好的答案。我的Python太大而无法显示,因此链接的here。
源文件are here:
将一堆xml文件附加到一个带有多个头文件的文件中。问题是在解析这个具有多个xml和dtd声明的非常规“非标准”XML文件时尝试使用正确的xpath表达式。我一直在尝试使用"-".join(doc.xpath
将所有内容绑定在一起解析出来,但输出会为下面显示的<document-id>
和<classification-national>
创建用连字符分隔的空格
<references-cited> <citation>
<patcit num="00001"> <document-id>
<country>US</country>
<doc-number>534632</doc-number>
<kind>A</kind>
<name>Coleman</name>
<date>18950200</date>
</document-id> </patcit>
<category>cited by examiner</category>
<classification-national><country>US</country>
<main-classification>249127</main-classification></classification-national>
</citation>
注意并非每个<citation>
内都存在所有儿童,有时他们根本不存在。
如何在尝试在<citation>
下的多个条目的每个数据条目之间放置连字符时解析此xpath?
答案 0 :(得分:1)
从这个XML(references.xml),
<references-cited>
<citation>
<patcit num="00001">
<document-id>
<country>US</country>
<doc-number>534632</doc-number>
<kind>A</kind>
<name>Coleman</name>
<date>18950200</date>
</document-id>
</patcit>
<category>cited by examiner</category>
<classification-national>
<country>US</country>
<main-classification>249127</main-classification>
</classification-national>
</citation>
<citation>
<patcit num="00002">
<document-id>
<country>US</country>
<doc-number>D28957</doc-number>
<kind>S</kind>
<name>Simon</name>
<date>18980600</date>
</document-id>
</patcit>
<category>cited by other</category>
</citation>
</references-cited>
您可以获取<citation>
的每个后代的文本内容,其内容如下:
from lxml import etree
doc = etree.parse("references.xml")
cits = doc.xpath('/references-cited/citation')
for c in cits:
descs = c.xpath('.//*')
for d in descs:
if d.text and d.text.strip():
print "%s: %s" %(d.tag, d.text)
print
输出:
country: US
doc-number: 534632
kind: A
name: Coleman
date: 18950200
category: cited by examiner
country: US
main-classification: 249127
country: US
doc-number: D28957
kind: S
name: Simon
date: 18980600
category: cited by other
此变体:
import sys
from lxml import etree
doc = etree.parse("references.xml")
cits = doc.xpath('/references-cited/citation')
for c in cits:
descs = c.xpath('.//*')
for d in descs:
if d.text and d.text.strip():
sys.stdout.write("-%s" %(d.text))
print
导致此输出:
-US-534632-A-Coleman-18950200-cited by examiner-US-249127
-US-D28957-S-Simon-18980600-cited by other