Question

我已经使用了很多次，但我无法理解为什么它现在不能正常工作。

我有3个模型Project，User和Country。

项目所属于用户用户所属国家

这是模型

<?php
class User extends AppModel {
    var $name = 'User';
    var $displayField = 'username';
    var $belongsTo = array(
        'AccountType' => array(
            'className' => 'AccountType',
            'foreignKey' => 'account_type_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'PaymentType' => array(
            'className' => 'PaymentType',
            'foreignKey' => 'payment_type_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'Country' => array(
            'className' => 'Country',
            'foreignKey' => 'country_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'InstantMessenger' => array(
            'className' => 'InstantMessenger',
            'foreignKey' => 'instant_messenger_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'TimeZone' => array(
            'className' => 'TimeZone',
            'foreignKey' => 'time_zone_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'Language' => array(
            'className' => 'Language',
            'foreignKey' => 'language_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
    );
}


<?php
class Project extends AppModel {
    var $name = 'Project';
    var $displayField = 'project_title';

    var $belongsTo = array(
            'User' => array(
                    'className' => 'User',
                    'conditions' => '',
                    'fields' => '',
                    'order' => ''
            ),
            'ProjectType' => array(
                    'className' => 'ProjectType',
                    'foreignKey' => 'project_type_id',
                    'conditions' => '',
                    'fields' => '',
                    'order' => ''
            ),
            'BiddingType' => array(
                    'className' => 'BiddingType',
                    'foreignKey' => 'bidding_type_id',
                    'conditions' => '',
                    'fields' => '',
                    'order' => ''
            ),
            'ProjectStatus' => array(
                    'className' => 'ProjectStatus',
                    'foreignKey' => 'project_status',
                    'conditions' => '',
                    'fields' => '',
                    'order' => ''
            ),
            'EmploymentType',
            'PaymentType',
    );
}



<?php
class Country extends AppModel {
    var $name = 'Country';
    var $displayField = 'name';
    //The Associations below have been created with all possible keys, those that are not needed can be removed

    var $hasMany = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'country_id',
            'dependent' => false,
            'conditions' => '',
            'fields' => '',
            'order' => '',
            'limit' => '',
            'offset' => '',
            'exclusive' => '',
            'finderQuery' => '',
            'counterQuery' => ''
        )
    );

}

现在，我的代码是尝试将可包含的项目附加到项目并添加用户

function smartbid($projid = null)
{
    $this->loadModel('Content');
    $content = $this->Content->findById(53);
    $this->set('content',$content);
    $this->Project->Behaviors->attach('Containable');
    $options = array(
       array(
        'conditions'=>
           array(
                'Project.id'=>$projid
            ),
           'contain'=>array(
               'User'
           )
        ) 
     );
    $project = $this->Project->find('first',$options);

    $this->set(compact('project'));
}

现在，cakephp完全忽略了我附加的containsable并返回此

）

你可以看到它忽略了我的依恋。我做错了什么。

Answer 1

这是一个相当古老的问题，但它的价值在哪里。

Here是可包含行为的文档。它声明，要动态加载行为，您应该使用：

$this->Model->Behaviors->load('Containable');

我认为差异仅仅是因为attach和detach已被弃用。

另外，为什么不在模型中设置$actAs属性，甚至在AppModel中设置？

class AppModel extends Model {
    public $actAs = array('Containable');
    // public $recursive = 0;
    //...
}

与User模型中定义的Project模型的关系缺少foreignKey字段，这可能会造成麻烦。我认为Cake默认为user_id，当然应该是projects表中列的名称。

除此之外，您对contain选项的使用似乎没问题。

Answer 2

试试这个：

$this->Project->Behaviors->attach('Containable');
$this->Project->contain(array(
            'conditions' => array('Project.id' => $projid),
            'User'));
$project = $this->Project->find('first');
$this->Project->Behaviors->detach('Containable');

Cakephp可以不附加到Model上

2 个答案: