我正在尝试正确连接三个进程,以便允许它们之间的进程间通信。我有一个进程,scan,它接受父进程STDIN,然后处理流中的单词。如果字长是奇数,则将其发送到一个进程,如果是偶数,则将其发送给另一个进程。这些过程应该通过STDIN(我假设)接受这些话,然后通过STDOUT将一些信息输出回扫描过程。偶数/奇数的STDOUT应重定向到扫描器,然后读取(使用读取)然后输出/处理字。这是一个学术练习,而不是一个实践练习。以下是它的图片:
这是我的代码目前的样子。问题是我不确定要复制什么以及要关闭什么。一旦我弄明白,我应该好好去!任何建议将不胜感激。
文件描述符:
int scannertoeven[2]; int scannertoodd[2];
int eventoscanner[2]; int oddtoscanner[2];
//Pipe stuff here (ommitted)
代码:
//Create the child processes
if ((scanner_pid = fork()) == 0) {
//We need the scanner pid so even and odd can send signals to it
char pidofparent[sizeof(getpid())];
sprintf(pidofparent, "%i", getpid());
//Even stuff
if ((even_pid = fork()) == 0) {
close(scannertoodd[0]); close(scannertoodd[1]);
close(oddtoscanner[0]); close(oddtoscanner[1]);
//Not sure which ones to close
close(scannertoeven[0]); close(scannertoeven[1]);
close(eventoscanner[0]); close(eventoscanner[1]);
//Correct?
close(STDIN_FILENO);
dup2(scannertoeven[0], STDIN_FILENO);
close(STDOUT_FILENO);
dup2(eventoscanner[1], STDOUT_FILENO);
if(execl("./evenodd", "even", pidofparent, NULL ) == -1) {
printf("execl Error!");
exit(1);
}
//Odd Stuff
} else if ((odd_pid = fork()) == 0){
close(scannertoeven[0]); close(scannertoeven[1]);
close(eventoscanner[0]); close(eventoscanner[1]);
//Not sure which ones to close
close(scannertoodd[0]); close(scannertoodd[1]);
close(oddtoscanner[0]); close(oddtoscanner[1]);
//Correct?
close(STDIN_FILENO);
dup2(scannertoodd[0], STDIN_FILENO);
close(STDOUT_FILENO);
dup2(oddtoscanner[1], STDOUT_FILENO);
if(execl("./evenodd", "odd", pidofparent, NULL ) == -1) {
printf("execl Error!");
exit(1);
}
//Actual Scanner
} else {
// Not sure which ones to close- this is very wrong
close(scannertoeven[0]); close(scannertoeven[1]);
close(eventoscanner[0]); close(eventoscanner[1]);
close(scannertoodd[0]); close(scannertoodd[1]);
close(oddtoscanner[0]); close(oddtoscanner[1]);
//Not sure what to dup either
dup2(scannertoodd[1], STDOUT_FILENO);
dup2(scannertoeven[1], STDOUT_FILENO);
if(execl("./scanner", "scanner", stoeven, stoodd, eventos, oddtos, NULL ) == -1) {
printf("execl Error!");
exit(1);
}
//Wait twice here, or three times in main?
waitpid(odd_pid, &status2, 0);
waitpid(even_pid, &status3, 0);
}
//Main
} else {
//Close Pipes
close(scannertoodd[0]); close(scannertoeven[0]); close(eventoscanner[0]); close(oddtoscanner[0]);
close(scannertoodd[1]); close(scannertoeven[1]); close(eventoscanner[1]); close(oddtoscanner[1]);
//Wait for children to finish
waitpid(scanner_pid, &status1, 0);
printf("Done\n");
}
答案 0 :(得分:3)
不确定逻辑。但是你使用dup2的方式不对。
“均匀”过程中的以下代码:
close(STDIN_FILENO);
dup2(scannertoeven[0], STDIN_FILENO);
close(STDOUT_FILENO);
dup2(eventoscanner[1], STDOUT_FILENO);
应该是:
dup2(scannertoeven[0], STDIN_FILENO);
// You should close scannertoeven[0], not STDIN. After this dup2, the even
// process will receive input from scannertoeven[0]
close(scannertoeven[0]);
// Note the the scannertoeven[0] is not "really" closed, just that the file
// is "attached" to STDIN
dup2(eventoscanner[1], STDOUT_FILENO);
// Same as above. After this dup2, all the even process's output will go
// to eventoscanner[1]
close(eventoscanner[1]);
与“奇怪”过程相同。
以下是an example of dup2,供您参考。