Question

我正在尝试使用Django-filetransfer上传文件，我想知道如何导入用户名作为保存上传文件的名称。现在我正在使用User.username，但那是无效。我想最重要的问题是如何从models.py访问用户的属性。下面是我的models.py:

from django.db import models
from django.contrib.auth.models import User, UserManager

class UploadModel(User,models.Model):
    title = models.CharField(max_length=64, blank=True)
    user = models.ForeignKey(User)
    file = models.FileField(upload_to='./uploads/'+str(User.username))


    @property
    def filename(self):
    return self.file.name.rsplit('/', 1)[-1]

更新： 应用程序/上传/ models.py

from django.db import models
from django.contrib.auth.models import User, UserManager

def uploadmodel_file_upload_to(instance, filename):
    return 'uploads/%s/%s' % (instance.user.username, filename)

class UploadModel(models.Model):
    user = models.ForeignKey('auth.user')
    file = models.FileField(upload_to=uploadmodel_file_upload_to)

/ upload上的TemplateSyntaxError 渲染时捕获DatabaseError：列upload_uploadmodel.user_id不存在第1行：选择“upload_uploadmodel”。“id”，“upload_uploadmodel”。“user ...

Answer 1

当Python解析models.py代码时，模型属性是正式定义的。您应该使用upload_to 的回调，使用用户相关实例生成上传文件路径，例如：

def uploadmodel_file_upload_to(instance, filename):
    return 'uploads/%s/%s' % (instance.user.username, filename)

class UploadModel(models.Model):
    user = models.ForeignKey('auth.user')
    file = models.FileField(upload_to=uploadmodel_file_upload_to)

Django文件传输保存到每个用户的新文件

1 个答案: