Question

这是我的代码

class InternalDevice1
{
}

class InternalDevice2
{
}

class SpecificDevice1 : InternalDevice1
{
}

class SpecificDevice2 : InternalDevice2
{
}

class SpecificDevice3 : InternalDevice1
{
}

class SpecificDevice4 : InternalDevice2
{
}

class MyWholeDevice1 : IDevice
{
   MyWholeDevice(SpecificDevice1 device1, SpecificDevice2 device2) { }
   SpecificDevice1 Device { get; }   
}

class MyWholeDevice2 : IDevice
{
   MyWholeDevice(SpecificDevice3 device1, SpecificDevice4 device2) { }
   SpecificDevice3 Device { get; }  
}


interface IDevice
{
   InternalDevice1 Device { get; }
}

问题是IDevice中的返回类型是InternalDevice1（更通用）虽然我需要SpecificDevice（仍然从InternalDevice中删除）我在尝试使用它时遇到了一个问题：

IDevice = new MyWholeDevice ...

Answer 1

您应该设置IDevice generic

interface IDevice<TDevice>
   where TDevice : InternalDevice1
{
   TDevice Device { get; }
}

然后你的课程将如下所示：

class MyWholeDevice1 : IDevice<SpecificDevice1>
{
   MyWholeDevice(SpecificDevice1 device1, SpecificDevice2 device2) { }
   SpecificDevice1 Device { get; }   
}

class MyWholeDevice2 : IDevice<SpecificDevice3>
{
   MyWholeDevice(SpecificDevice3 device1, SpecificDevice4 device2) { }
   SpecificDevice3 Device { get; }  
}

使用基类创建接口，而派生类包含自己的实现

1 个答案: