Question

我正在制作一个简单的绘画程序，并且我很难获得字符串的某个部分。这就是问题 - 当我保存9面板图像时，它会将每个面板的RBG值存储到.txt文件中。示例：

java.awt.Color [r = 0，g = 0，b = 0]
java.awt.Color [r = 255，g = 255，b = 255]
java.awt.Color [r = 255，g = 0，b = 0]
java.awt.Color [r = 0，g = 0，b = 255]
java.awt.Color [r = 0，g = 0，b = 0]
java.awt.Color [r = 255，g = 255，b = 0]
java.awt.Color [r = 255，g = 255，b = 0]
java.awt.Color [r = 255，g = 0，b = 0]
java.awt.Color [r = 0，g = 0，b = 255]

从这里，我打电话给扫描仪来读取我们文件的行。我只需要找到将[]中的值提取到String的最佳方法。我已经尝试使用一个令牌器无济于事，仍然被多余的字符串困住。我试过操纵角色但又失败了。从括号中提取数据的最佳方法是什么？并且将单个r = xxx，b = xxx，g = xxx值存储到String []会更容易吗？谢谢，这是我到目前为止的来源：

import java.awt.Color;
import java.io.*;
import java.lang.*;
import java.util.*;
//when finished, organize imports (narrow down what imports were used)

public class SaveLoad {

private boolean tryPassed, tryPassed2;

private Formatter x;
//final String[] rawData; will be where the rgb raws are stored

private Scanner xReader;

public void save(Color[] c, String s) {
    //s is the filename
    int counter = c.length;

    //Tries to create a file and, if it does, adds the data to it.
    try{
        x = new Formatter(s+".txt");
        tryPassed = true;
        while(counter>0) {
            x.format("%s. %s\n", (c.length-(counter-1)), c[counter-1]);
            counter--;
        }
        x.close();
    }catch (Exception e){
        e.printStackTrace();
        tryPassed = false;
    }
}

//load will take paramaters of a filename(string); NOTE:::: make the file loaded specify an appendix (ex] .pixmap)
//MAYBE add a load interface with a jDropdownmenu for the filetype? add parameter String filetype.
public void load(String s, String filetype) {
    //loads the file and, if successful, attempts to read it.
    try{
        xReader = new Scanner(new File(s+filetype));
        tryPassed2 = true;
    }catch(Exception e){
        e.printStackTrace();
        tryPassed2 = false;
        System.out.println(s+filetype+" is not a valid file");
    }
    while(xReader.hasNext()&&tryPassed2==true) {
        String inBrackets = xReader.next().substring(17);
        System.out.println(inBrackets);
    }
}
}

另外，忽略我凌乱的记谱法。

Answer 1

最好的方法是更改存储格式。至少有两个选择：

逗号分隔值。在每行上存储r,g,b。例如215,222,213。然后，您可以line.split(",")获取值String[]
使用Color

ObjectOutputStream

Answer 2

我建议改变格式。但如果你坚持使用正则表达式：

    String st = "java.awt.Color[r=0,g=0,b=0]";
    Pattern p = Pattern.compile("java.awt.Color\\[r=(.*),g=(.*),b=(.*)\\]");

    Matcher m = p.matcher(st);

    if (m.matches()) {
        System.out.println("r=" + m.group(1));
        System.out.println("g=" + m.group(2));
        System.out.println("b=" + m.group(3));
    }

从字符串中获取值

2 个答案: