Question

我有一个这样的视图文件：

<html>
<head>
        <meta name="layout" content="main" />
        <title><g:message code="User's profile" /></title>
        <g:javascript library="jquery"/>
        <g:javascript>
         (function() {
              jQuery(function() {
                return $(window).scroll(function() {
                  var url;
                  url = $('.pagination .nextLink').attr('href');
                  if (url && $(window).scrollTop() > $(document).height() - $(window).height() - 50) {
                    $('.pagination').show();
                    $('.pagination').text('Fetching more tasks, please wait!...');
                    return $.get(url, function(data) {
                      $('#scrolling').append(data);
                      return $('.pagination').hide();
                    });
                  }
                });
              });
            }).call(this);
        </g:javascript>
</head>
<body>
    <!--Render the menu for the user-->
        <!--check the size of the task so that we can diplay a meaningful mess if userTasks is empty!-->
        <g:if test = "${userTasks.size() > 0}" >
        <div id = "scrolling">
            <g:each in = "${userTasks}" var = "tasks">
                <div class = "scrolling">
                    <span style = "position:relative; left:360px; font-size:1.2em;"><g:link controller = "tasks" action = "show2" id = "${tasks.id}">${tasks.title}</g:link> </span>
                </div>
            </g:each>
            <div class = "pagination">
                <g:paginate total = "${tasksCount}" controller = "tasks" action = "test" />
            </div>
        </g:if>
        <g:else>
            You don't have any unread tasks!
        </g:else>
        </div>
    <br />
</body>
</html>

这与Twitter网站非常相似，当用户向下滚动页面底部时，i / e将获取更多结果，这将重复进行。这对我有用，但我现在遇到的问题不是单独更新我的id scrolling部分，而是让整个页面再次重新加载并使页面看起来很讨厌！

以下是我的网页外观： enter image description here

当我的滚动条点击页面底部时，您可以清楚地看到我的整页布局正在重新加载。我怎么能摆脱这个？

提前致谢。

Answer 1

试试这个：

 (function() {
      jQuery(function() {
        return $(window).scroll(function() {
          var url;
          url = $('.pagination .nextLink').attr('href');
          if (url && $(window).scrollTop() > $(document).height() - $(window).height() - 50) {
            $('.pagination').show();
            $('.pagination').text('Fetching more tasks, please wait!...');
            $.get(url, function(data) {
              $("#scrolling").append($(data).filter("#scrolling").html());
              $('.pagination').hide();
            });
            return $('#scrolling').load(url + " #scrolling", function() {
              return $('.pagination').hide();
            });
          }
        });
      });
    }).call(this);

如何在Grails中通过Jquery仅更新所需的ID？

1 个答案: