Question

为了在网格中输出它，我必须具有如下所示的JSON语法：

{
"data": [
    {
        "SupplierID": 1,
        "CompanyName": "Exotic Liquids",
        "ContactName": "Charlotte Cooper",
        "ContactTitle": "Purchasing Manager",
        "Address": "49 Gilbert St.",
        "City": "London",
        "Region": null,
        "PostalCode": "EC1 4SD",
        "Country": "UK",
        "Phone": "(171) 555-2222",
        "Fax": null,
        "HomePage": null
    },
    {
        "SupplierID": 2,
        "CompanyName": "New Orleans Cajun Delights",
        "ContactName": "Shelley Burke",
        "ContactTitle": "Order Administrator",
        "Address": "P.O. Box 78934",
        "City": "New Orleans",
        "Region": "LA",
        "PostalCode": "70117",
        "Country": "USA",
        "Phone": "(100) 555-4822",
        "Fax": null,
        "HomePage": "#CAJUN.HTM#"
    },....more data...
        ]
}

这是我正在使用的代码：

mysql_connect('localhost','root','')or die(mysql_error());
mysql_select_db('testdb')or die(mysql_error());
$result = mysql_query("select * from city");
$data[]=array();
while($rows=mysql_fetch_array($result,MYSQL_ASSOC)){
 $jsondata=json_encode($rows);
 echo $data[$jsondata];
}

但我有一些错误。 Notice: Undefined index:

我该如何解决这个问题？谢谢

Answer 1

您需要先将编码数据添加到数组

$data =array();
while($rows=mysql_fetch_array($result,MYSQL_ASSOC)){
 $jsondata=json_encode($rows);
 $data[] = $jsondata;
}

现在你可以回应整个事情（可能有一种更简单的方法）

echo explode( $data, ',' );

另外，我认为你可以一次编码整个数组。

Answer 2

您过早地编码数据。通常你应该构造整个多维数组，然后才进行编码

mysql_select_db('testdb') or die(mysql_error());
$result = mysql_query("select * from city");

$data = array('data' => array());
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $data['data'][] = $row;
}

echo json_encode($data);

JSON数组中的语法

2 个答案: