Question

最好，最简单的方法是什么？我的查询目前是：

  SELECT * 
    FROM chat 
   WHERE (userID = $session AND toID = $friendID) 
      OR (userID = $friendID AND toID = $session) 
ORDER BY id 
   LIMIT 10

这显示前10行，而不是最后10行。

编辑：我想要最后10行（是的，DESC这样做）但是我希望它们以ASCENDING顺序返回。

Answer 1

要撤销订单（因此获得最后10个而不是前10个），请使用DESC代替ASC

修改

根据您的评论：

SELECT * FROM ( SELECT * FROM chat WHERE (userID = $session AND toID = $friendID) OR (userID = $friendID AND toID = $session) ORDER BY id DESC LIMIT 10 ) AS `table` ORDER by id ASC

Answer 2

如果你想要最后10个，那么只需将ASC更改为DESC

SELECT * 
FROM 
chat 
WHERE 
(userID=$session AND toID=$friendID) 
OR 
(userID=$friendID AND toID=$session) 
ORDER BY id 
DESC
LIMIT 10

Answer 3

                $con = mysqli_connect("localhost","my_user","my_password","my_db");
                $limit = 10;                
                $query = "SELECT * FROM  $table";
                $resource = mysqli_query($con,$query);
                $total_rows = mysqli_num_rows($resource);
                $start = $total_rows-$limit;
                $query_limit= $query." LIMIT $start,$limit";

首先我设定了限制

$limit = 10;

然后

 $total_rows = mysqli_num_rows($resource);

这里我采取了受影响的总行数。

$start = $total_rows-$limit;

然后从行数减去限制以获取起始记录号

   $query_limit= $query." LIMIT $start,$limit";

然后为查询添加限制。有关限制的更多信息，请参阅此链接 https://www.w3schools.com/php/php_mysql_select_limit.asp

Answer 4

首先从表格中选择最后10个，然后以升序对其重新排序。

SELECT * FROM (SELECT * FROM table ORDER BY id DESC LIMIT 10) sub ORDER BY id ASC

MYSQL从表中选择，获取表中的最新/最后10行

4 个答案: