Question

我有这个家庭作业，要求用户输入数字，然后计算平均中位数和模式，然后询问他/她是否想再次播放，重复程序或退出。一切都在编译，但我似乎可以弄清楚出现的一些问题：

卑鄙的作品。中位数没有。如果整数数组具有偶数长度，即数组中的4个数字，则中位数应该是平均的两个中间数。所以如果数字按顺序为“1,3,5,6”，则中位数应为4.000000。该模式也不起作用，当被要求“再次播放？”时任何答案都会导致程序突然退出并崩溃。有人可以帮助我找到我的平均中位模式计算中的错误，并帮我菜单？

#define MAX 25
#include <stdio.h>
#include <stdbool.h>
#include <time.h>
#include <stdlib.h>

int readTotalNums();
void fillArray(int total, int nums[]);
void sortArray(int nums[], int total);
double findMean(int nums[], int total);
double findMedian(int nums[], int total);
int findMode(int nums[], int total);
void printResults(double mean, double median, double mode);
bool goAgain();

int main()  {
    int nums[MAX];
    int total;
    double mean, median, mode;
    do {
        total = readTotalNums(); //guarantee 1-25
        fillArray(total, nums); //read in the #s don't need to check range
        sortArray(nums, total);
        mean = findMean(nums, total);
        median = findMedian(nums, total);
        mode = findMode(nums, total);
        printResults(mean, median, mode);
    } while (goAgain());
    return 0;
}

int readTotalNums() {
    int num;
    do {
        printf("How many numbers? ");
        scanf("%i", &num);
    } while (num < 1 || num > 25);
    return num;
}

void fillArray(int total, int nums[]) {
    int temp;
    int i;
    printf("Please enter %i numbers\n", total);
    for (i = 0; i <= total-1; i++) {
        scanf("\n%i",&nums[i]);
    }
}

void sortArray(int nums[], int total) {
int x;
int y;
for(x=0; x<total; x++) {
    for(y=0; y<total-1; y++) {
        if(nums[y]>nums[y+1]) {
            int temp = nums[y+1];
            nums[y+1] = nums[y];
            nums[y] = temp;
        }
    }
}
}

double findMean(int nums[], int total) {
    int i;
    double sum = 0.0;
    for(i = 0; i < total; i++) {
        sum += nums[i];
    }
    return (sum/total);
}

double findMedian(int nums[], int total) {
    int temp;
    int i,j;
    for(i=0;i<total;i++)
        for(j=i+1;j<total;j++) {
            if(nums[i]>nums[j]) {
                temp=nums[j];
                nums[j]=nums[i];
                nums[i]=temp;
            }
        }
        if(total%2==0) {
            return (nums[total/2]+nums[total/2-1])/2;
        }else{
            return nums[total/2];
        }
}

int findMode(int nums[],int total) {
    int i, j, maxCount, modeValue;
    int tally[total];
    for (i = 0; i < total; i++) {
         tally[nums[i]]++;
    }
    maxCount = 0;
    modeValue = 0;
    for (j = 0; j < total; j++) {
        if (tally[j] > maxCount) {
            maxCount = tally[j];
            modeValue = j;
        }
    }
    return modeValue;
}

void printResults(double mean, double median, double mode) {
    printf("Mean: %d\tMedian: %d\tMode: %i", mean, median, mode);
}


bool goAgain() {
    char *temp;
    printf("\nWould you like to play again(Y/N)? ");
    scanf("%s", &temp);
    while (temp != 'n' && temp != 'N' && temp != 'y' && temp != 'Y') {
        printf("\nI am sorry that is invalid -- try again");
        printf("\nWould you like to play again(Y/N)? ");
        scanf("%s", &temp);
    }
    if (temp == 'y' || temp == 'Y') {
        return true;
    } else {
        return false;
    }
}

输出应该是这样的：

How many numbers 4
Please enter 4 numbers
6
2
5
25
 Mean: 9.50 Median:  5.50   Mode:  2
Go again (y/n) n

Answer 1

好吧，我发现了3个问题：

你的printf错了。要打印double，您应该使用%f。不是%d或%i。
您应该在使用前初始化tally。
在goAgain中，temp应为char，您应使用%c代替%s。

Answer 2

对于findMedian，您无需对整个数组进行排序。

for(i=0;i < int(total/2)+1;i++)

会好的。

计算平均中值模式c编程数组

2 个答案: