填充GridView问题

时间:2012-02-23 16:49:59

标签: java android gridview multidimensional-array

所以我一直在使用网格视图来处理我的应用程序中的几个问题,这个问题现在让我烦恼,因为我在大约一周的尝试后无法解决问题。

我正在尝试使用当前存储在多维数组中的时间表填充网格视图,但是填充的唯一索引是第一个。我的BaseAdapter类的副本如下:

    package com.ian.calendar.event;

import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.TextView;
import com.ian.calendar.database.DatabaseHandler;
import com.ian.campusmap.R;

public class ModuleEvents extends BaseAdapter {

    private String weekday;
    private Context context;
    private View view;
    private TextView[] textView;
    private DatabaseHandler dbHandler;
    private int eventNumber;
    private String[][] moduleA;

    public ModuleEvents(Context _context, String _weekday) {
        context = _context;
        weekday = _weekday;
        dbHandler = new DatabaseHandler(context);
        dbHandler.populateDatabase();
        dbHandler.getTimeTable();
    }

    public int getCount() {
        return 6;
    }

    public View getView(int position, View convertView, ViewGroup parent) {
        int i = 1;
        eventNumber = getEventsOnWeekday();
        moduleA = new String[eventNumber][6];
        textView = new TextView[eventNumber];

        do {
            if(weekday.equals(dbHandler.getTimeTableWeekday(i))) {
                for(int j = 0; j < eventNumber; j++) {
                    moduleA[j][0] = dbHandler.listArray(i, 0);
                    moduleA[j][1] = dbHandler.listArray(i, 1);
                    moduleA[j][2] = dbHandler.listArray(i, 3);
                    moduleA[j][3] = dbHandler.listArray(i, 5);
                    moduleA[j][4] = dbHandler.listArray(i, 6);
                    moduleA[j][5] = dbHandler.listArray(i, 2);
                    i++;
                }
            } else {
                i++;
            }
        } while(i < dbHandler.count);

        if(convertView == null) {
            LayoutInflater inflater = (LayoutInflater) 
                context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

            view = inflater.inflate(R.layout.grid_item_2, null);
        }

        for(int k = 0; k < moduleA.length; k++) {
            textView[k] = new TextView(context);
            textView[k] = (TextView) view.findViewById(R.id.txtModuleID);
            textView[k].setText(moduleA[k][position]);
        }

        return view;
    }

    public Object getItem(int arg0) {
        return null;
    }

    public long getItemId(int arg0) {
        return 0;
    }

    public int getEventsOnWeekday() {
        int events = 0;
        for(int i = 1; i <= 9; i++) {
            if(weekday.equals(dbHandler.getTimeTableWeekday(i))) {
                events++;
            }
        }
        return events;
    }
}

如果您需要任何其他类源代码,请随时询问。

编辑:忘记添加可能有一些冗余代码,我还没有删除。遗憾!

Edit2:摆脱了phtrivier

提到的do / while循环

Edit3:我想没有人知道......

1 个答案:

答案 0 :(得分:0)

这部分看起来很可疑:

        do {
            return textView[k];
        } while(l < moduleA.length);

如果意味着你的“getView”函数将始终返回第一个TextView,那就是...