我有一个问题:
SELECT count(itemlogger2_finds.player_id) AS ile, itemlogger2_finds.player_id,
itemlogger2_players.name FROM itemlogger2_finds, itemlogger2_players WHERE
itemlogger2_finds.method='-1' AND itemlogger2_finds.time>'1329951599' AND
itemlogger2_finds.time<'1330556399' AND itemlogger2_players.id = itemlogger2_finds.player_id
GROUP BY itemlogger2_finds.player_id ORDER BY 1 DESC LIMIT 10;
表 itemlogger2_finds:
player_id | method | time
itemlogger2_players:
id | name
现在,当我使用我的查询时,显示名称,player_id和项目计数
itemlogger2_finds.time>'1329951599' AND
itemlogger2_finds.time<'1330556399'
我需要同时计算3件物品。
示例:
player_id | method | time
1 | -1 | 1329951699
1 | -1 | 1329951699
1 | -1 | 1329951699
1 | -1 | 1329951699
1 | -1 | 1329951699
现在我的计数是5,我需要同时计算3次。