绝对坐标位图android

时间:2012-02-23 10:41:58

标签: android bitmap coordinates surfaceview

我有一个尺寸大于屏幕的位图(即1000x1000)。我可以通过画布拖动这个位图。如果我在点(500,500)getX或getY不返回500除了0和320 [屏幕大小模拟器]之间的某个值,所以我需要知道关于点0的绝对值。我希望我的视图不要将位图转换为超过视图的0左和0顶点

我提出了一些代码来澄清问题

public MapaView(Context context, AttributeSet attrs) {
    super(context, attrs);

    mScaleDetector = new ScaleGestureDetector(context, new ScaleListener());
    mSurfaceHeight = 640;
    mSurfaceWidth = 480;
    mapaActual = new Mapa();
    mContext = context;
    mBufferedCanvas = new Canvas();

}


    draw(Canvas c){ 

    bitmapAux.eraseColor(Color.WHITE);

   /*draw the rectangles....*/

    c.translate(mPosX, mPosY);
    c.scale(mScaleFactor, mScaleFactor);
    c.drawBitmap(bitmapAux, 0, 0, null);}

我通过下一个方法得到了位置

@Override
    public boolean onTouchEvent(MotionEvent ev) {
        // Let the ScaleGestureDetector inspect all events.
        mScaleDetector.onTouchEvent(ev);


        final int action = ev.getAction();
        switch (action & MotionEvent.ACTION_MASK) {
        case MotionEvent.ACTION_DOWN: {
            startTime = ev.getEventTime();
            final float x = ev.getX();
            final float y = ev.getY();
            final float xR= ev.getRawX();
            final float yR= ev.getRawY();
            movido=false;
            mLastTouchX = x;
            mLastTouchY = y;
            mLastTouchXRaw = xR;
            mLastTouchYRaw = yR;

            mActivePointerId = ev.getPointerId(0);

            break;
        }

        case MotionEvent.ACTION_MOVE: {
            final int pointerIndex = ev.findPointerIndex(mActivePointerId);
            final float x = ev.getX(pointerIndex);
            final float y = ev.getY(pointerIndex);

            // Only move if the ScaleGestureDetector isn't processing a gesture.
            if (!mScaleDetector.isInProgress()) {
                final float dx = x - mLastTouchX;
                final float dy = y - mLastTouchY;

                mPosX += dx;
                mPosY += dy;

                movido=true;
                invalidate();
            }

            mLastTouchX = x;
            mLastTouchY = y;
            movido=true;


            break;
        }

        case MotionEvent.ACTION_UP: {
            mActivePointerId = INVALID_POINTER_ID;
            endTime = ev.getEventTime();

            if ((endTime - startTime > 500)&&!movido) {

                // we have a 1000ms duration touch
                // propagate your own event
                Log.d("LC", "time touched greater than 1000ms " + endTime + "  "
                        + startTime);

                startTime = 0;
                endTime = 0;
                movido=false;
                Box pepeBox=new Box();
                pepeBox=buscarElemento();
                //Intent intent=new Intent(mContext,OpcionesConceptoList.class);
                //mContext.startActivity(intent);
                /*
                 * return true; notify that you handled this event (do not
                 * propagate)
                 */
            }
            break;
        }

        case MotionEvent.ACTION_CANCEL: {
            mActivePointerId = INVALID_POINTER_ID;
            break;
        }

        case MotionEvent.ACTION_POINTER_UP: {
            final int pointerIndex = (ev.getAction() & MotionEvent.ACTION_POINTER_INDEX_MASK) >> MotionEvent.ACTION_POINTER_INDEX_SHIFT;
            final int pointerId = ev.getPointerId(pointerIndex);
            if (pointerId == mActivePointerId) {
                // This was our active pointer going up. Choose a new
                // active pointer and adjust accordingly.
                final int newPointerIndex = pointerIndex == 0 ? 1 : 0;
                mLastTouchX = ev.getX(newPointerIndex);
                mLastTouchY = ev.getY(newPointerIndex);
                mActivePointerId = ev.getPointerId(newPointerIndex);
            }
            break;
        }

        }



        return true;
    }

有什么建议吗?

提前致谢并原谅我的英语。

2 个答案:

答案 0 :(得分:1)

getRawX()和getRawY():返回相对于手机屏幕的坐标(X,Y)

getX()和getY():返回相对于视图的坐标(X,Y)。

实际上是什么绝对的坐标?

答案 1 :(得分:0)

如果我理解你的问题,

//
Bitmap bitmap;
//
//
double bitmapRatio  = ((double)bitmap.getWidth())/bitmap.getHeight()

DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
double screenHeight = metrics.heightPixels;
double screenWidth = metrics.widthPixels;

double screenRatio= screenWidth /screenHeight;

if(bitmapRatio  > screenRatio){

}else{

}