为什么我在这里得到java.lang.StackOverflowError?

时间:2012-02-23 06:37:35

标签: java exception recursion stack-overflow factorial

_以下问题的以下程序提供了一系列例外Exception in thread "main" java.lang.StackOverflowError at testing_package.Compute.factorial(Compute.java:105)我不明白为什么会出现此错误。

问题:N个男孩和M个女孩正在从剧院学习表演技巧。进行比赛  他们需要组成一组P演员,其中包含不少于4个男孩和不少于1个女孩。该  剧院要求你写一个程序,告诉他们组的形成方式的数量。  注意:组成应该是唯一的,而不是组成的顺序。

import java.io.*;

class Compute {

private static int NFact;
private static int N_Minus_R_Fact;
private static int RFact;
private static int fact=0;

public static int readTheStrengthOfGroup() {
    int strengthOfGroup=0;
    try {
        System.out.println("Enter the strength of group : ");
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String read = reader.readLine();
        strengthOfGroup = Integer.parseInt(read);
    } catch(Exception exc) {
        System.out.println(exc);
      }
      return strengthOfGroup;
}

public static int readTheNumberOfBoys() {
   int boysToParticipate=0;
   try {
    System.out.println("Enter the number of boys to participate in the play : ");
    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    String read = reader.readLine();
    boysToParticipate = Integer.parseInt(read);
   } catch(Exception exc) {
        System.out.println(exc);
     }
    return boysToParticipate;
}

public static int readTheNumberOfGirls() {
    int girlsToParticipate=0;
    try {
        System.out.println("Enter the number of girls to participate in the play : ");
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String read = reader.readLine();
        girlsToParticipate = Integer.parseInt(read);
    } catch(Exception exc) {
        System.out.println(exc);
      }
    return girlsToParticipate;
}

public static int compute(int strengthOfGroup , int boysToParticipate , int girlsToParticipate) {
    if( boysToParticipate < 4 || girlsToParticipate < 1) {
        return 0;
    } else {
        /*  P >= 5 
         *  N : Boys
         *  M : Girls
         *  result = M+N C P - { (N C 0)(M C P)+(N C 1)(M C P-1)+(N C 2)(M C P-2)+(N C 3)(M C P-3)+(N C P)(M C 0) }
         */
         int resultP_2 = 0;
         int totalNumberOfParticipants = boysToParticipate + girlsToParticipate;
         int totalNumberOfParticipants_C_strengthOfGroup = computeFactorial(totalNumberOfParticipants , strengthOfGroup);
         for( int i = 0 ; i <= 4 ; i++ ) {
                          if( i == 4 ) {
                resultP_2 = resultP_2 + (computeFactorial(boysToParticipate,strengthOfGroup) * computeFactorial(girlsToParticipate,0)); 
            }else {
            resultP_2 = resultP_2 + (computeFactorial(boysToParticipate,i) * computeFactorial(girlsToParticipate,strengthOfGroup));
            strengthOfGroup--;}
         }
         int result = totalNumberOfParticipants_C_strengthOfGroup - resultP_2;
         return result;
      }
}

public static int computeFactorial(int N , int R) {
    if(R > N) {
        throw new RuntimeException("Invalid Parameters");
    } else {
        /* int NFact;
        int N_Minus_R_Fact;
        int RFact; */
        NFact = factorial(N);
        N_Minus_R_Fact = factorial(N-R);
        RFact = factorial(R);
        return( NFact / ( N_Minus_R_Fact-RFact ) );

      }
}

public static int factorial(int num) {
    if( num == 1 ) {
        return 1;
    } else {
        fact = num * factorial(num-1); // LINE 105
        return fact;
      }
}

public static void main(String args[]) {
    int strengthOfGroup = readTheStrengthOfGroup();
    int boysToParticipate = readTheNumberOfBoys();
    int girlsToParticipate = readTheNumberOfGirls();
    int result = compute(strengthOfGroup , boysToParticipate , girlsToParticipate);
    System.out.println("Number of groups that can be formed : " + result);
}

}

我评论了第105行。 enter image description here

1 个答案:

答案 0 :(得分:6)

computeFactorial避免在factorial时调用R > N,但在所有其他情况下调用R == NR < N),传入N-R 。如果R == N,则N-R0。在factorial中,您要检查num == 1是否返回1,但当num0时,您正在调用factorial使用num - 1-1。然后它会使用num - 1再次调用自己,-2,依此类推,负数越来越大(-1-2,...),直到你用完了。

我没有仔细阅读过这些代码,但至少在factorial以及1 {{{}时需要num == 0返回num == 1 1}})。如果你给它一个负数,我也会抛出异常。