Question

我正在尝试通过从我的iOS应用程序向php脚本发送POST请求来验证用户身份。然后让iOS应用程序读取NSHTTPURLResponse以确定它是否成功。我的iOS代码如下所示，由于某种原因，它说我的NSURLConnection未使用。 int代码总是返回值为200。

- (void)authenticateUser:(NSString *)aUsername
                password:(NSString *)aPassword
{
    NSString *post = [NSString stringWithFormat:@"username=%@&pw=%@", aUsername, aPassword];
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%d", [post length]];

    NSURL *url = [NSURL URLWithString:@"http://XXX.com/query-db.php"];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody:postData];

    NSURLConnection *theConnection = [NSURLConnection connectionWithRequest:request delegate:self];
}

- (void) connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response{
    NSHTTPURLResponse* httpResponse = (NSHTTPURLResponse*)response;
    int code = [httpResponse statusCode];

    // Log the response
    NSLog(@"%d", code);
    if(code == 1){
        NSLog(@"received a 1");
        [self updateWorkTime];
        //[self close];
    } else {
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Unsuccessul Attempt" message:@"The username or password is invalid, please try again." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
        [alert show];
        [alert release];
    }
}

另外，如果你想看看我的php脚本，我在虚拟变量中输入并测试它是否正确查询数据库并检查出来...但是以防你好奇。

<?php
    $sentUsername = $_POST['username'];
    $sentPW = $_POST['pw'];

    mysql_connect("xxx", "xxx", "xxx") or die(mysql_error());   
    mysql_select_db("xxx") or die(mysql_error());

    $result = mysql_query("SELECT * FROM Table") or die(mysql_error());  

    $authenticate = 0;

    while($authenticate == 0) {
        $row = mysql_fetch_array($result);
        $selectedUsername = $row['username'];
        $selectedPW = $row['pw'];
        $pwComp = strcmp($sentPW, $selectedPW);
        $userComp = strcmp($selectedUsername, $sentUsername);

        if(!$row) break;
        if($selectedPW == $sentPW && $selectedUsername == $sentUsername) {
            $authenticate = 1;
        }
    }
    echo $authenticate;
?>

我尝试设置PHP标头，但我不确定如何做到这一点。我感谢这个社区给予我的任何和所有帮助，真正无价之宝。谢谢！

Answer 1

您收到的'200'代码是HTTP状态代码，表示请求成功。

如果您正在从PHP脚本发回“1”或“0”值之后，您应该使用didReceiveData:委托方法，而不是didReceiveResponse:来查找它。

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)theData
{
    NSLog(@"authenticate value => %@",[[NSString alloc] initWithData:theData encoding:NSUTF8StringEncoding]);
}

Answer 2

您正在使用NSASCIIStringEncoding - 尝试使用NSUTF8StringEncoding - 您可能会在转换为NSData对象时丢失它。

此外，您应该使用HTTPS，否则您的密码对所有人都可见： - ）

尝试通过将用户名/密码发送到PHP脚本来验证iOS中的用户

2 个答案: