Question

所以我有一个返回此JSON的Web服务：

[{"other_user":"54","distance":"1 ft","duration":"1 min"},{"other_user":"55","distance":"2 ft","duration":"5 min"}]

然后在我的ios应用程序中使用：

NSString *responseString = [request responseString];
    NSArray *responseArray = [responseString JSONValue];
    for (NSDictionary* item in responseArray) {
        NSString *otherUser = [item objectForKey:@"other_user"];
        NSString *otherDistance = [item objectForKey:@"distance"];
        NSString *otherDuration = [item objectForKey:@"duration"];

       NSLog(@"user: %@  distance: %@  time: %@", otherUser, otherDistance, otherDuration);
    }

但是我收到了这个错误：

-JSONValue failed. Error is: Illegal start of token [S]

感谢任何帮助，我不知道在哪里查看/调试

Answer 1

尝试以下方法：

SBJSON *parser = [[SBJSON alloc] init];
NSString *responseString = [request responseString];

NSError *jsonError=nil;
NSArray *responseArray = [parser objectWithString: responseString error: &jsonError];

if (jsonError==nil) {
   for (NSDictionary* item in responseArray) {
      NSString *otherUser = [item objectForKey:@"other_user"];
      NSString *otherDistance = [item objectForKey:@"distance"];
      NSString *otherDuration = [item objectForKey:@"duration"];

      NSLog(@"user: %@  distance: %@  time: %@", otherUser, otherDistance, otherDuration);
   }
}

祝你好运

吨

JSON iOS失败错误

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